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mafiozo [28]
4 years ago
7

Hey everyone I’m struggling with this can you help?

Mathematics
1 answer:
telo118 [61]4 years ago
4 0
Click on the picture to see how I got -17x-21 as the answer

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The area of a square is 9 centimeters squared (cm^2) If the sides of the square are doubled in length, what is the new area, in
Mice21 [21]

Answer:

The question says area of a square = 9 cm squared.

And they said if the sides are doubled in length what is the new length

so new length = 9 cm^2 × 9 cm^2

which should give you 81cm^2

therefore your answer should be = C

7 0
3 years ago
Read 2 more answers
Find the coordinates of the midpoint of a line segment with end points (-3,4) and (7,9)
lesantik [10]

Answer:  (2, 6.5)

<u>Step-by-step explanation:</u>

Midpoint_{x,y}=\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\\.\qquad \qquad \quad=\bigg(\dfrac{-3+7}{2},\dfrac{4+9}{2}\bigg)\\\\\\.\qquad \qquad \quad=\bigg(\dfrac{4}{2},\dfrac{13}{2}\bigg)\\\\\\.\qquad \qquad \quad=\large\boxed{(2,6.5)}

6 0
3 years ago
What are the missing parts that correctly complete the proof
bonufazy [111]

Answer:

2. \overline{AX}\cong \overline{BX}

3. PX \perp AB - definition of perpendicular

4. \angle PXA \cong \angle PXB - all right angles are congruent

6. \triangle AXP\cong \triangle BXP

7. \overline{PA} \cong \overline{PB}

Step-by-step explanation:

<u>Given: </u>Point P is the perpendicular bisector of AB

<u>Prove: </u>P is equidistant from the endpoints AB

<u>Proof.</u>

1. Point P is on the perpendicular bisector of AB - given

2.\overline{AX}\cong \overline{BX} - definition of bisector

3. PX \perp AB - definition of perpendicular

4.  \angle PXA \cong \angle PXB - all right angles are congruent

5. \overline{PX} \cong \overline{PX} - reflexive property of congruence

6. \triangle AXP\cong \triangle BXP - SAS congruency postulate

7. \overline{PA} \cong \overline{PB} - corresponding parts of congruent triangles are congruent

8. Point P is equidistant from the endpoints of AB - definition of equidistant

5 0
3 years ago
Anybody know the correct answer to this?
Digiron [165]

A=\{x|x=3n,\ n\in\{2,\ 3,\ 4\}\}=\{(3)(2),\ (3)(3),\ (3)(4)\}=\{6,\ 9,\ 12\}\\\\B=\{x|x=4m-3,\ m\in\{1,\ 2,\ 3\}\}\\=\{(4)(1)-3,\ (4)(2)-3,\ (4)(3)-3\}=\{1,\ 5,\ 9\}\\\\A\ \cap\ B=\{9\}

Answer: 9

4 0
3 years ago
PLS HELP ASAP!!!!!!!!!!!
ivolga24 [154]

Answer:

No, Jude’s graph is incorrect. The inequality symbol is “less than,” so -9 is not included. He should have used an open circle on -9.

^ sample response

sorry that im late on this, but i hope it helps anyone else : )

3 0
3 years ago
Read 2 more answers
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