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wlad13 [49]
3 years ago
7

Find all the powers of 4 in the range 4 Through 1000

Mathematics
2 answers:
Delvig [45]3 years ago
8 0
We want to find all 4^x less than 1000 and greater than or equal to 4. They are 4, 4*4, 4*4*4... or 4, 16, 64, 256.

Anettt [7]3 years ago
7 0
(4⁰  =  1  too small)

4¹  =  4

4² = 16

4³ = 64

4⁴ = 256

(4⁵ = 1,024  too big)

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If the price of the item drops by 60% then that means the new price is 40% of the original

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If p(x) = 2x2 – 4x and q(x) = x – 3, what is mc007-1.jpg? 2x2 – 4x + 12 2x2 – 16x + 18 2x2 – 16x + 30 2x2 – 16x + 15
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You are planning on applying to the Knirhsdaeh institute as a psychology counselor. They hire millions of psychologists around t
elena-14-01-66 [18.8K]

Answer:

The 98% of the confidence interval for the true average salary of Knirhsdaeh employees as a psychology counselor

(75.4206, 86.5794)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the mean of the sample = $81 k</em>

<em>Given that the size of the sample 'n' = 23</em>

<em>Given that the standard deviation for the salaries is $13 k</em>

<u><em>Step(ii):-</em></u>

<u><em>98% of the confidence interval for the true average salary of Knirhsdaeh employees is determined by</em></u>

<u><em /></u>(x^{-} - t_{0.02} \frac{S.D}{\sqrt{n} } , x^{-} + t_{0.02} \frac{S.D}{\sqrt{n} })<u><em /></u>

<u><em>Degrees of freedom = n-1 = 23-1 =22</em></u>

<u><em /></u>t_{0.02} = 2.5083<u><em /></u>

(81 - 2.0583 \frac{13}{\sqrt{23} } , 81 + 2.0583 \frac{13}{\sqrt{23} } )

( 81 - 5.57940 , 81 + 5.57940)

(75.4206, 86.5794)

<u><em>Final answer:-</em></u>

The 98% of the confidence interval for the true average salary of Knirhsdaeh employees as a psychology counselor

(75.4206, 86.5794)

7 0
3 years ago
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