Answer:
a. Time=25seconds
b.distance=1041.67m
Explanation:
a.The equation for in terms of m/s is
after conversion.
To find when speed reaches 300km/hr=83.33m/s, we find and solve for
b. From a, above we already have our t=25seconds as the time it takes before the plane is airborne.
#To find distance travelled in that time , we substitute for in our distance equation:
Hence the distance of the plane before it gets airborne is 1041.67m
Answer:
see explanation
Explanation:
You are missing the chart with the rates and time to do this, however, I wll do it with a similar exercise here, and you only need to replace the procedure with your data:
See the attached table.
From the left we have:
r = 1/2 (50 + 48 + 46 + 44 + 42 + 40) = 135 L/min
From the right we have:
r = 1/2 (48 + 46 +44 + 42 + 40 + 38) = 129 L/min.
And this should be the correct answer. Watch your chart and replace if it's neccesary.
Answer:
Explanation:
is the magnetic quantum number.
The only possible value for the magnetic quantum number for an electron in an s orbital is 0.
The first three quantun numbers are:
This quantum number is related to the type (or shape) of the orbital:
For s orbitals
For p orbitals
For d orbitals
For f orbitals
In this case, it is an s orbital, so we have .
Since, for the s orbitals , the only possible value for
is zero.