How do crystalline solids differ from amorphous solids?
1 answer:
You might be interested in
Mass of the block = 1.4 kg
Weight of the block = mg = 1.4 × 9.8 = 13.72 N
Normal force from the surface (N) = 13.72 N
Acceleration = 1.25 m/s^2
Let the coefficient of kinetic friction be μ
Friction force = μN
F(net) = ma
μmg = ma
μg = a
μ =
μ =
μ = 0.1275
Hence, the coefficient of kinetic friction is: μ = 0.1275
Answer:
Explanation:
Given
mass of boy=36 kg
length of swing=3.5 m
Let T be the tension in the swing
At top point
where v=velocity needed to complete circular path
Th-resold velocity is given by
So apparent weight of boy will be zero at top when it travels with a velocity of
To get the velocity at bottom conserve energy at Top and bottom
At top
Energy at Bottom
Comparing two as energy is conserved
Apparent weight at bottom is given by