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Mice21 [21]
3 years ago
6

Please help me..........

Physics
2 answers:
natali 33 [55]3 years ago
8 0

Answer:

force

Explanation:

pushing something forward

Lemur [1.5K]3 years ago
4 0

Answer:

2nd one Force

Explanation:

Without a source of force and object won't have the capability of moving.

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Waves in the ocean are _____ traveling along the water
Mice21 [21]
The answer is energy.

Waves in the ocean are energy travelling along water.

Waves do not transport mass, they transport energy, this is the ability to perform work or exert force and distant points.

Although water seems to be travelling along with the wave, the molecules of water only move up and down; they do not travel along with the wave.
4 0
3 years ago
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A physics student stands on a cliff overlooking a lake and decides to throw a softball to her friends in the water below. She th
Andre45 [30]

The horizontal distance covered by the ball before hitting the water is 70.4 m

Explanation:

The motion of the ball is the motion of a projectile, so it consists of two independent motions:

  • A uniform motion along the horizontal (x) direction
  • A uniformly accelerated motion along the vertical (y) direction

We start by calculating the time of flight of the ball. This can be done by analyzing the vertical motion. We can use the following suvat equation:

s=u_y t + \frac{1}{2}at^2

where:

s = -16.5 m is the vertical displacement of the ball (it is negative because we take upward as positive direction)

u_y is the initial vertical velocity of the ball, which is given by

u_y = u sin \theta

where

u = 23.5 m/s is the initial velocity

\theta=33.5^{\circ} is the angle of projection

Substituting,

u_y=(23.5)(sin 33.5^{\circ})=13.0 m/s

a=g=-9.8 m/s^2 is the acceleration of gravity, downward

Substituting everything into the equation we get:

-16.5=13.0t-4.9t^2\\4.9t^2-13.0t-16.5=0

Solving the equation for t, we find the time of flight of the ball:

t = -0.94 s

t = 3.59 s

We ignore the 1st solution since it is negative, so the ball reaches the water after 3.59 seconds.

Now we analyze the horizontal motion of the ball. The horizontal velocity is constant and it is:

v_x=u cos \theta=(23.5)(cos 33.5^{\circ})=19.6 m/s

Therefore, the horizontal distance covered in a time t is

d=v_x t

And substituting t = 3.59 s, we find

d=(19.6)(3.59)=70.4 m

So, the horizontal distance covered by the ball before hitting the water is 70.4 m.

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

4 0
4 years ago
Two people of different masses sit on a seesaw. M1, the mass of person 1, is 91 kg, M2 is 45 kg, d1 = 0.8 m, and d2 = 1.1 m. The
mash [69]

Answer:

1/ 485.6 Nm

2/ Clock-wise

3/ 0 and no direction

4/ 1.62 m

Explanation:

1/ Torque is gravity force times the moment arm. Let's g = 9.81m/s2

T_2 = m_2*g*d_2 = 45*9.81*1.1 = 485.6 Nm

2/ If person 2 is sitting on the right, the direction of this torque is clock-wise, since the gravity is acting downward.

3/ Assuming that location A is right at the pivot point, then the torque generated by this torque is 0, since the moment arm is 0. This has no direction.

4/ The seasaw is balanced, this means torques generated by 2 people are equal and in opposite direction

T_1 = T_2

m_1gd_1 = m_2g_d_2

m_1d_1 = m_2d_2

d_2 = \frac{m_1d_1}{m_2} = \frac{91*0.8}{45} = 1.62m

So the new location for d2 is 1.62m

5 0
3 years ago
In which type of process is there no change in the pressure of the system?
Lubov Fominskaja [6]
The answer is C hahaha
6 0
3 years ago
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Please help me with my question
Rufina [12.5K]
Number 1!!!!!!!!!!!!!

6 0
3 years ago
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