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2 years ago

Please help me..........

Physics

2 answers:

natali 33 [55]2 years ago

8 0

Answer:

force

Explanation:

pushing something forward

Lemur [1.5K]2 years ago

4 0

Answer:

2nd one Force

Explanation:

Without a source of force and object won't have the capability of moving.

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The rotating loop in an AC generator is a square 10.0 cm on each side. It is rotated at 60.0 Hz in a uniform field of 0.800 TO.

Genrish500 [490]

Answer:

Explanation:

Given a square side loop of length 10cm

L=10cm=0.1m

Then, Area=L²

Area=0.1²

Area=0.01m²

Given that, frequency=60Hz

And magnetic field B=0.8T

a. Flux Φ

Flux is given as

Φ=BA Sin(wt)

w=2πf

Φ=BA Sin(2πft)

Φ=0.8×0.01 Sin(2×π×60t)

Φ=0.008Sin(120πt) Weber

b. EMF in loop

Emf is given as

EMF= -N dΦ/dt

Where N is number of turns

Φ=0.008Sin(120πt)

dΦ/dt= 0.008×120Cos(120πt)

dΦ/dt= 0.96Cos(120πt)

Emf=-NdΦ/dt

Emf=-0.96NCos(120πt). Volts

c. Current induced for a resistance of 1ohms

From ohms law, V=iR

Therefore, Emf=iR

i=EMF/R

i=-0.96NCos(120πt) / 1

i=-0.96NCos(120πt) Ampere

d. Power delivered to the loop

Power is given as

P=IV

P=-0.96NCos(120πt)•-0.96NCos(120πt)

P=0.92N²Cos²(120πt) Watt

e. Torque

Torque is given as

τ=iL²B

τ=-0.96NCos(120πt)•0.1²×0.8

τ=-0.00768NCos(120πt) Nm

8 0

2 years ago

Tubby and his twin brother Libby have a combined mass of 200 kg and are zooming along in a 100 kg amusement park bumper car at 1

harkovskaia [24]

Answer: 14.1 m/s

Explanation:

We can solve this with the Conservation of Linear Momentum principle, which states the initial momentum $p_{i}$ (before the elastic collision) must be equal to the final momentum $p_{f}$ (after the elastic collision):

$p_{i}=p_{f}$ (1)

Being:

$p_{i}=m_{1}V_{i} + m_{2}U_{i}$

$p_{f}=m_{1}V_{f} + m_{2}U_{f}$

Where:

$m_{1}=200 kg +100 kg=300 kg$ is the combined mass of Tubby and Libby with the car

$V_{i}=10 m/s$ is the velocity of Tubby and Libby with the car before the collision

$m_{2}=25 kg + 100 kg=125 kg$ is the combined mass of Flubby with its car

$U_{i}=0 m/s$ is the velocity of Flubby with the car before the collision

$V_{f}=4.12 m/s$ is the velocity of Tubby and Libby with the car after the collision

$U_{f}$ is the velocity of Flubby with the car after the collision

So, we have the following:

$m_{1}V_{i} + m_{2}U_{i}=m_{1}V_{f} + m_{2}U_{f}$ (2)

Finding $U_{f}$ :

$U_{f}=\frac{m_{1}(V_{i}-V_{f})}{m_{2}}$ (3)

$U_{f}=\frac{300 kg(10 m/s-4.12 m/s)}{125 kg}$ (4)

Finally:

$U_{f}=14.1 m/s$

8 0

3 years ago

A 24 volt battery is connected to a 3Ω resistor and a 5Ω resistor in series. What is the current in the circuit?

Vladimir [108]

Answer: 3 Amperes

Explanation:

Voltage of battery = 24 volts

R1 = 3Ω

R2 = 5Ω

Total resistance = ?

Current, I = ?

Since the resistors are connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.

i.e Rtotal = R1 + R2

Rtotal = 3Ω + 5Ω = 8Ω

Now recall that voltage = current x resistance

i.e V = I x Rtotal

24volts = I x 8Ω

I = 24 volts / 8Ω

I = 3 amperes

Thus, there is 3 Amperes of current in the circuit

7 0

3 years ago

I need help ASAP!

san4es73 [151]

Answer:

Explanation:

7 0

2 years ago

A VHF television station assigned to channel 4 transmits its signal using radio waves with a frequency of 66.0 MHz. Calculate th

soldi70 [24.7K]

Answer:

The wavelength is 4.55 m.

Explanation:

Given data

Frequency (ν): 66.0 MHz = 66.0 × 10⁶ Hz = 66.0 × 10⁶ s⁻¹

Speed of light (c): 3.00 × 10⁸ m/s

Wavelength (λ): To be found

We can determine the wavelength of the radio waves using the following expression.

c = λ × ν

λ = c / ν

λ = (3.00 × 10⁸ m/s)/66.0 × 10⁶ s⁻¹

λ = 4.55 m

6 0

2 years ago