Question

The temperature of the ideal gas in the container is 300 K the gas occupies a volume of 1.27 m^3 what would be the volume of the gas if it's temperature were decreased to 100K no blocks are added or removed from the lid

Answer 1

Answer:

0.42 m³

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T1) = 300 K

Initial volume = 1.27 m³

Final temperature (T2) = 100 K

Final volume (V2) =?

The final volume of the gas can be obtained by using the Charles' equation as illustrated below:

V1/T1 = V2/T2

1.27 / 300 = V2 / 100

Cross multiply

300 × V2 = 1.27 × 100

300 × V2 = 127

Divide both side by 300

V2 = 127 / 300

V2 = 0.42 m³

Therefore, the new volume of the gas is 0.42 m³