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irina [24]
3 years ago
10

What is the electron configuration of the element with 27 protons?

Chemistry
2 answers:
adelina 88 [10]3 years ago
7 0
<span>The electronic configuration of cobalt is :1s2 2s2 2p6 3s2 3p6 3d7 4s2 </span>
Pavel [41]3 years ago
5 0

Answer: Co:27:1s^22s^22p^63s^23p^64s^23d^7

Explanation: A neutral element with 27 protons will have 27 electrons and thus has a atomic number of 27. The element with atomic number 27 is cobalt and the nearest noble gas is argon with 18 electrons.

The electrons are filled according to Afbau's rule in order of increasing energies.

Co:27:1s^22s^22p^63s^23p^64s^23d^7

The electronic configuration in terms of noble gs configuration is:  

Co:27:[Ar]4s^23d^7

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<h3>Answer:</h3>

62.3 mol Ca

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
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<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.75 × 10²⁵ atoms Ca

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.75 \cdot 10^{25} \ atoms \ Ca(\frac{1 \ mol \ Ca}{6.022 \cdot 10^{23} \ atoms \ Ca})
  2. Multiply/Divide:                \displaystyle 62.2717 \ mol \ Ca

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

62.2717 mol Ca ≈ 62.3 mol Ca

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