The moon's mass is only outnumbered by Earth's mass, which is 81 times greater. This indicates that while it moves in a circle, the circle is substantially smaller than usual. The core of the circle that the Earth revolves around is really inside the planet.
In space, there is gravity. It is gravity that makes the moon orbit. Everything in orbit, including the moon, is falling freely. That entails letting gravity operate as it pleases. Because you continually missing the object you are orbiting, an orbit is like a fall that never makes it to the earth; by the time you arrive at the spot where the object was, you have overshot, and it is now behind you.
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The work done to pull the object 7.0 m is the total area under the graph from 0.0 m to 7.0 m, determined as 245 J.
<h3>Work done by the applied force</h3>
The area under force versus displacement graph is work done.
The total work done by pulling the object 7 m, can be grouped into two areas;
- First area, A1 = area of triangle from 0 m to 2.0 m
- Second area, A2 = area of trapezium, from 2.0 m to 7.0 m
A1 = ¹/₂ bh
A1 = ¹/₂ x (2) x (20)
A1 = 20 J
A2 = ¹/₂(large base + small base) x height
A2 = ¹/₂[(7 - 2) + (7-3)] x 50
A2 = ¹/₂(5 + 4) x 50
A2 = 225 J
<h3>Total work done </h3>
W = A1 + A2
W = 20 J + 225 J
W = 245 J
Learn more about work done here: brainly.com/question/8119756
Ok? I don’t know what you want me to do though
Using the constant acceleration formula v^2 = u^2 + 2as, we can figure out that it would take a distance of 193.21m to reach 27.8m/s
