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yawa3891 [41]
3 years ago
10

During adverse weather conditions such as rain or fog, drivers should take action accordingly by turning on their headlights, sl

owing down and increasing
Physics
1 answer:
xeze [42]3 years ago
4 0
<span>During adverse weather conditions such as rain or fog, drivers should take action accordingly by turning on their headlights, slowing down and increasing following distance. Adverse weather means that you are driving in difficult and dangerous conditions. Increasing following distance will help you to maintain safe driving and avoid tailgating. </span>
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An object is accelerating from rest at a rate of 3 m/s2.How long will it take the object to attain 18 m/s ? *
Temka [501]
Initial velocity =0, a=3m/s2, final velocity =18m/s, 18=3t, t=6 sec
7 0
3 years ago
Name the quantity which is measured by the area occupied below the velocity time graph
kiruha [24]

If you mark off a beginning time and ending time on the graph,
then the area under the part of the graph between those limits
is the distance covered during that period of time.

3 0
3 years ago
Read 2 more answers
You are driving to the grocery store at 18 m/sm/s. You are 160 mm from an intersection when the traffic light turns red. Assume
inysia [295]

Answer:

part(a) 151 m

part(b) 1.073 m/s2

part(c) 16.7 secs

Explanation:Firstly the person applied brakes 0.5 secs after seeing the red light hence the distance traveled during this time is

d=v*t

d=18*0.5

d=9m

For part (a)

I have corrected this question and now

The person was 160m from the intersection before applying the brakes as he traveled 9m before the brakes

He is now 151 m from intersection as

s=160-9

s= 151 m

part (b)

As it is given that velocity of the car is 0 at the intersection so we use this information in kinematic equation

v^2=u^2+2as

here u=18m/s and s=151

0=18^2+2a*151\\302a=-324\\a=-1.073 m/s^2

To calculate time we can use the acceleration equation

a=\frac{v-u}{t} \\t=\frac{v-u}{a}\\t=18/1.073\\t=16.77 secs

6 0
3 years ago
A solid block of metal is at its melting temperature. it takes 24j to melt 6kg of a metal. what is the latent heat of fusion of
Marina86 [1]

The Latent heat of fusion is also known as the Enthalpy of Fusion. It is a kind pf change in enthalpy.

<h3>Brief explanation of Latent Heat of Fusion? </h3>

The latent heat of fusion, is the change in enthalpy that takes place when energy, typically heat, is provided to a specific quantity of a substance to causes it to change from a solid state to a liquid state at a constant pressure.

For instance, 1 kilogram of ice melts at 0 °C at a variety of pressures, absorbing 333.55 kJ of energy without causing a change in temperature.

The heat of solidification, which occurs when a substance changes from a liquid to a solid, is equal and opposing.

This energy includes the contribution necessary to displace its surroundings against ambient pressure in order to accommodate any corresponding change in volume.

The melting point or the freezing point, depending on the situation, is the temperature at which the phase transition takes place. Conventionally, unless otherwise stated, the pressure is taken to be 1 atm (101.325 kPa).

<h3>Calculation</h3>

The formula of latent heat of fusion is L= q/m

Here q is the heat provided and m is the mass of the object.

So, L = 24j/6kg

L= 4j/kg

So, the latent heat of fusion is 4 j/kg

To know more about latent Heat of Fusion visit:

brainly.com/question/28044951

#SPJ4

8 0
2 years ago
Please help on this one?
jekas [21]
It should be A) Force increases
8 0
4 years ago
Read 2 more answers
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