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ankoles [38]
3 years ago
8

In redox half-reactions, a more positive standard reduction potential means I. the oxidized form has a higher affinity for elect

rons. II. the oxidized form has a lower affinity for electrons. III. the reduced form has a higher affinity for electrons. IV. the greater the tendency for the oxidized form to accept electrons.
Chemistry
1 answer:
qwelly [4]3 years ago
4 0

Answer:

The 1st and 4th options are correct

I.the oxidized form has a higher affinity for electrons

IV. the greater the tendency for the oxidized form to accept electrons

Explanation:

Half reaction can be described as the oxidation or reduction reaction in a redox reaction.it is In the redox rection there is a change in the oxidation states of Chemical species involved. the oxidized form in the redox has a higher affinity for electrons and the greater the tendency for the oxidized form to accept electrons.

Standard reduction potential which is also referred to as standard cell potential can be described as the potential difference that exist between cathode and anode of the cell. In the standard reduction potential most times the species will be reduced which is usually analysed in a reduction half reaction.

(Standard Hydrogen Electrode) is utilized when determining the Standard reduction or potentials of a chemical specie. this is because of Hydrogen having zero reduction and oxidation potentials, as a result of this a measured potential of any species is compared with that of Hydrogen, the difference helps to know the potential reduction of that particular specie.

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What is the percent-by-mass concentration of acetic acid (CH3COOH) in a vinegar solution that contains 51.80 g acetic acid in a
Semenov [28]

Answer : The percent-by-mass concentration of acetic acid is, 5.15 %

Explanation : Given,

Mass of acetic acid = 51.80 g

Density of solution = 1.005 g/ml

Volume of solution = 1.000 L = 1000 ml      (1 L = 1000 ml)

First we have to calculate the mass of solution.

\text{Mass of solution}=\text{Density of solution}\times \text{Volume of solution}

\text{Mass of solution}=1.005g/ml\times 1000ml=1005g

Now we have to calculate the percent-by-mass concentration of acetic acid.

\% \text{ by mass of acetic acid}=\frac{\text{Mass of acetic acid}}{\text{Mass of solution}}\times 100

Now put all the given values in this formula, we get:

\% \text{ by mass of acetic acid}=\frac{51.80g}{1005g}\times 100=5.15\%

Therefore, the percent-by-mass concentration of acetic acid is, 5.15 %

6 0
3 years ago
If one of the reactants in a reaction is Na2O, what is known about the products?
const2013 [10]

D. The products will have at least 2 Na atoms and 1 O atom.

<h3>Further explanation</h3>

If we refer to the law of mass conservation, which states that

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Like an example of this Na₂O reaction:

Na₂O + H₂O ⇒ 2 NaOH

Na : left =2, right = 2

O : left=2, right = 2

4 0
3 years ago
Read 2 more answers
I need help plz with the first question plz
Cloud [144]
Ok so put it in order
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