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ankoles [38]
3 years ago
8

In redox half-reactions, a more positive standard reduction potential means I. the oxidized form has a higher affinity for elect

rons. II. the oxidized form has a lower affinity for electrons. III. the reduced form has a higher affinity for electrons. IV. the greater the tendency for the oxidized form to accept electrons.
Chemistry
1 answer:
qwelly [4]3 years ago
4 0

Answer:

The 1st and 4th options are correct

I.the oxidized form has a higher affinity for electrons

IV. the greater the tendency for the oxidized form to accept electrons

Explanation:

Half reaction can be described as the oxidation or reduction reaction in a redox reaction.it is In the redox rection there is a change in the oxidation states of Chemical species involved. the oxidized form in the redox has a higher affinity for electrons and the greater the tendency for the oxidized form to accept electrons.

Standard reduction potential which is also referred to as standard cell potential can be described as the potential difference that exist between cathode and anode of the cell. In the standard reduction potential most times the species will be reduced which is usually analysed in a reduction half reaction.

(Standard Hydrogen Electrode) is utilized when determining the Standard reduction or potentials of a chemical specie. this is because of Hydrogen having zero reduction and oxidation potentials, as a result of this a measured potential of any species is compared with that of Hydrogen, the difference helps to know the potential reduction of that particular specie.

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Honeybee venom is a solution that contains formic acid, which gives the venom an approximate ph of 5.0. which substance is more
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5 0
3 years ago
The mass lost by the positive electron should equal the mass gained by the negative electrode suggest two reasons why the result
vesna_86 [32]

Answer:

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3 0
2 years ago
A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200
34kurt

Answer:

81 °C

Explanation:

This is a calorimetry question so a few things you will need for this. The calorimetry equation q=mcΔT & the specific heat of water (4.2J/g•°C). Other definitions are:

q = heat added/released by a sample

m = mass of sample

c=specific heat of sample

ΔT = change in temperature

from here we can rearrange the equation to state:

q/(mc) = ΔT

1200J/((20.0g)(4.2J/g•°C)) = ΔT

14°C = ΔT

If the starting temperature was 95.0°C and we know that the temperature was cooled by 14°C then the final temperature of the water would be 81.

4 0
2 years ago
How much time is required to plate out 20.0 g of Zn from a solution containing Zn2+ ions, using a current of 2.00 amperes?
lyudmila [28]

Answer: 494.872mins

Explanation:

M= MrIt÷n

M=20g

Mr=65g/mol

I=2A

1 farad= 96500

For zinc with 2ions

2×96500= 193000

M×n= MrIt

T= M×n÷MrI

t= 20×193000/2×65

t= 3860000/130

t= 29692.307sec

t=29692.307/60

t= 494.872 mins

7 0
3 years ago
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