Answer : The percent-by-mass concentration of acetic acid is, 5.15 %
Explanation : Given,
Mass of acetic acid = 51.80 g
Density of solution = 1.005 g/ml
Volume of solution = 1.000 L = 1000 ml (1 L = 1000 ml)
First we have to calculate the mass of solution.


Now we have to calculate the percent-by-mass concentration of acetic acid.

Now put all the given values in this formula, we get:

Therefore, the percent-by-mass concentration of acetic acid is, 5.15 %
D.
The products will have at least 2 Na atoms and 1 O atom.
<h3>Further explanation</h3>
If we refer to the law of mass conservation, which states that
<em>In a closed system, the masses before and after the reaction are the same
</em>
then the number of atoms in the reactance will be the same as the number of atoms in the product
In this problem it is known that Na₂O is one of the reactants so that the product of Na atoms and O atoms will at least equal the number of atoms in the bond, namely 2 Na and 1 O
Like an example of this Na₂O reaction:
Na₂O + H₂O ⇒ 2 NaOH
Na : left =2, right = 2
O : left=2, right = 2
I THINK that that is true. It's just weathering the rock down not change composition. Lemme know if you get it right please! (: