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Vikentia [17]
3 years ago
7

A mass slider m = 0.200 kg rests on a frictionless horizontal air rail connected to a spring with a force constant k = 5.00 N /

m. You pull the slider, stretching the spring 0.100 m, and then release it from rest. The slider returns to its equilibrium position (x = 0). What speed does it have when x = 0.080 m?

Physics
1 answer:
Step2247 [10]3 years ago
5 0
Va ser 0.0900 yo creo preo que esta respuesta te ayude
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1) 5.5 N

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m \frac{v^2}{R} is the centripetal force, which points upward, with

v = 5.22 m/s being the speed of the ball

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2) 3.9 N

When the ball is at the side of the circle, the only force acting along the centripetal direction is the tension in the string, therefore the equation of the forces becomes:

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T+mg=m\frac{v^2}{R}

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