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natima [27]
3 years ago
5

The most important barriers to diffusion today are physical features of Earth's surface.

Physics
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

False

Explanation:

Physical features of earth's surface like mountains, deserts and oceans are not the barriers in today's modern world. Technological improvements in the transportation and communication has removed these barriers. So they are not barriers anymore.

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What is the speed of a vehicle that travels 50 meters in 5 seconds m/s
katrin [286]

Answer:

10m/s

Explanation:

S=D/T

S=50m/ 5sec (make sure to write correct units, they sometimes mark you on that in physics)

S=10 m/sec (be careful of what the units that they want the answer in, different story if it was m/min

7 0
3 years ago
Read 2 more answers
How many different values of l are possible for an electron with principal quantum number n=5?
lions [1.4K]

Answer:

different value to l if n=5 are 0,1,2,3,4

7 0
3 years ago
For 10 minutes, the wolf blew on the brick house with 5,000 N of force. How much work did he do?
frozen [14]
C.0 because it didn't move<span />
8 0
3 years ago
A test charge of +3 µC is at a point P where the electric field due to the other charges is directed to the right and has a magn
umka2103 [35]

Answer:

Electric field will remain same.

Explanation:

Given that

At initial condition ,charge q = +3μ C

Electric field E = 4106 N/c

As we know that

Electric field due to charge q

E=\dfrac{kq}{r^2}  

Now when charge is replaced by new charge q'= -3μ C

From the expression of electric field we can say that electric field will remain same from same quantity of electric charge.

So we can say that electric field will remain same.

5 0
4 years ago
Two long, parallel wires are separated by a distance of 2.00 cm . The force per unit length that each wire exerts on the other i
RUDIKE [14]

Answer:

a) current in the second wire is 5.60A

b) opposite directions

Explanation:

a) We need to find the current of wire, the magnitude of the force per unit length between the two wires carrying current I and I¹ is given by

\frac{F}{L} = \frac{U_0I^1}{2\pi r} \\\\I^1 = \frac{F2\pi r}{LU_0I}

= (3.6 * 10^-^5)\frac{2\pi (0.02)}{4\pi * 10^-^7)(0.64)} \\= 5.60A

b) knowing that for a two parallel conductor carrying current in the same direction attracts each other, and for a two parallel conductors carrying carying current in opposite direction repels eachother.

therefore, since the two wire repel each other then the current in the second wire must flow in the opposite direction of the current in the first wire.

7 0
4 years ago
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