Answer:
Explanation:
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In this case, since the decomposition of sodium hydrogen carbonate is:
Thus, since there is a 2:1 mole ratio between the sodium hydrogen carbonate and sodium carbonate, and the molar masses are 84.01 and 105.99 g/mol respectively, we obtain the following theoretical yield:
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Let initially there are 10 molecules of O2 and 3 molecules of C3H8 present
The reaction will be
C3H8(g) + 5O2(g) ----> 3CO2(g) + 4H2O
so here oxygen molecules are limiting as for 3 molecules of C3H8 we need 15 molecules of O2
now the given 10 molecules of O2 will react with only 2 molecules of C3H8 and they will form six molecules of CO2 and 8 molecules of H2O
Hence answer is
molecules of CO2 formed = 6
Molecules of H2O formed = 8
molecules of C3H8 left = 1
molecules of O2 left = 0
Oxygen (6O2) and Glucose (C6H12O6)
<span>Reference: 6CO2 + 6H2O + light energy = C6H12O6 + 6O2.</span>
Answer:
1. K<10−3
Explanation:
Equilibrium Constant is an expression which involves the concentration of the product divided by the concentration of the reactant molecules.
However the concentration of the pure liquid and pure solid is regarded as 1.
Equilibrium expression for the equation 2H2(g)+O2(g)⇌2H2O(g)
Equilibrium Constant = [H2O]^2/[H2]^2 x [O2]
Since H2O is a pure liquid, its concentration = 1
There fore;
Equilibrium Constant = 1/[H2]^2 x [O2]
This shows that the Equilibrium Constant of the equation will be less than 1 and greater than 0.
Because all the compounds are at the same concentration, the one that can produce more particles in solution will be the one that will raise the boiling point the most.
<span>A. 2.0 M (NH4)3PO4 will produce 4 particles per molecule formula</span>
