r^2 = (4-3)^2 + (3-6)^2 + (-5-1)^2
r^2 = 1 + 9 + 36
r = sqrt(46)
The equation is:
(x-3)^2 + (y-6)^2 + (z-1)^2 = sqrt(46)
y = - 3(x + 1 )² + 2
the equation of a quadratic in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
here vertex = (- 1, 2), hence
y = a(x + 1)² + 2
to find a substitute (1, - 10) into the equation
- 10 = 4a + 2 ⇒ 4a = - 12 ⇒ a = - 3
y = - 3(x + 1)² + 2 ← in vertex form
Answer:
she subtracted the 5 instead of adding it
Step-by-step explanation: