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Harlamova29_29 [7]
3 years ago
15

You are asked to design a cylindrical steel rod 50.0 cm long, with a circular cross section, that will conduct 170.0 J/s from a

furnace at 350.0 ∘C to a container of boiling water under 1 atmosphere.
Physics
1 answer:
zepelin [54]3 years ago
5 0

Answer:

You are asked to design a cylindrical steel rod 50.0 cm long, with a circular cross section, that will conduct 170.0 J/s from a furnace at 350.0 ∘C to a container of boiling water under 1 atmosphere.

Explanation:

Given Values:

L = 50 cm = 0.5 m

H = 170 j/s

To find the diameter of the rod, we have to find the area of the rod using the following formula.

Here Tc = 100.0° C

        k  = 50.2

       H = k × A × \frac{[T_{H -}T_{C} ] }{L}

Solving for A

       A  =  \frac{H * L }{k * [ T_{H}- T_{C} ] }

       A  = \frac{170 * 0.5}{50.2 * [ 350 - 100 ]}

       A  = \frac{85}{12550} = 6.77 ×10^{-3} m²

Now Area of cylinder is :

     A =  \frac{\pi }{4} d²

solving for d:

    d =  \sqrt{\frac{4 * 0.00677 }{\pi } }

    d  = 9.28 cm

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