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Harlamova29_29 [7]
4 years ago
15

You are asked to design a cylindrical steel rod 50.0 cm long, with a circular cross section, that will conduct 170.0 J/s from a

furnace at 350.0 ∘C to a container of boiling water under 1 atmosphere.
Physics
1 answer:
zepelin [54]4 years ago
5 0

Answer:

You are asked to design a cylindrical steel rod 50.0 cm long, with a circular cross section, that will conduct 170.0 J/s from a furnace at 350.0 ∘C to a container of boiling water under 1 atmosphere.

Explanation:

Given Values:

L = 50 cm = 0.5 m

H = 170 j/s

To find the diameter of the rod, we have to find the area of the rod using the following formula.

Here Tc = 100.0° C

        k  = 50.2

       H = k × A × \frac{[T_{H -}T_{C} ] }{L}

Solving for A

       A  =  \frac{H * L }{k * [ T_{H}- T_{C} ] }

       A  = \frac{170 * 0.5}{50.2 * [ 350 - 100 ]}

       A  = \frac{85}{12550} = 6.77 ×10^{-3} m²

Now Area of cylinder is :

     A =  \frac{\pi }{4} d²

solving for d:

    d =  \sqrt{\frac{4 * 0.00677 }{\pi } }

    d  = 9.28 cm

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<h3>What is conduction?</h3>

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A 6.72 particle moves through a region of space where an electric field of magnitude 1270 N/C points in the positive direction,
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Answer:

                    v_{y}  = -104 m/s

Explanation:

Using:

Force = electric field * charge

F=e*q

Force = magnitude of charge * velocity * magnetic field * sin tither

F_{x2}= |q|*v*B*sin \alpha

Force on particle due to electric field:

     F_{x1}= E*q = (1270N/C)*(-6.72*10^{-6} ) = -8.53*10^{-3}

Force on particle due to magnetic field:

F_{x2}= |q|*v*B*sin \alpha  = (6.72*10^{-6} )*(1.15)*(sin90)*v = (7.728*10^{-6})*(v)

F_{x2} is in the positive x direction as F_{x1} is in the negative x direction while net force is in the positive x direction.

Magnetic field is in the positive Z direction, net force is in the positive x direction.

According to right hand rule, Force acting on particle is perpendicular to the direction of magnetic field and velocity of particle. This would mean the force is along the y-axis. As this is a negatively charged particle, the direction of the velocity of the particle is reversed. Therefore velocity of particle, v, has to be in the negative y direction.

Now,

                    F_{xnet}- F_{x1 } = F_{x2 }

                    (6.13*10^{-3}) - (8.53*10^{-3} ) = (7.728*10^{-6})*(v)

                    v = (F_{xnet}  - F_{x1}) / (F_{x2} )

                        =((6.13*10^{-3} ) - (8.53*10^{-3})) / (7.728*10^{-6})

                       = (- 104.25) m/s

                      v_{y}  = -104 m/s

8 0
3 years ago
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