Answer:
1.1 Two poles: North and South Poles.
1.2 - Staple pin - Nail - Tip of my phone charger - Metal keys - Cloth Hanger
1.3 - Wooden bed cot - Plastic pen - Game pad - Wooden shelf - Paper - A T-shirt
1.4 Yes
1.5 No
The speed of the sound wave in the medium, given the data is 3900 m
<h3>Velocity of a wave </h3>
The velocity of a wave is related to its frequency and wavelength according to the following equation:
Velocity (v) = wavelength (λ) × frequency (f)
v = λf
With the above formula, we can obtain the speed of the sound wave. Details below:
<h3>How to determine speed of the sound wave</h3>
The speed of the wave can be obtained as illustrated below:
- Frequency (f) = 600 Hz
- Wavelength (λ) = 6.5 m
- Velocity (v) =?
v = λf
v = 6.5 × 600
v = 3900 m
Thus, the speed of the sound wave in the medium is 3900 m
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Answer:
Explanation:
Point P is situated outside sphere . For a non conducting sphere , electric field outside sphere is given by the relation
E = k Q / d²
15000 = 9 x 10⁹ x Q / .5²
Q = 416.67 X 10⁻⁹
Maximum field will be when d = r ( radius )
maximum E = kQ / r²
= 9 x 10⁹ x 416.67 X 10⁻⁹ / .3²
= 41667 N / C
Answer:
K = m g (h₀ - h_plat)
Explanation:
Let's use energy conservation to solve this problem, write the energy at two points of interest
Initial. Higher
E_initial = m g h₀
Final. Lower
E_end = K + Ep
E_end = ½ m v² + m g h_plat
Energy is conserved
E_initial = E_end
m g h₀ = K + m g h_plat
K = m g (h₀ - h_plat)
<em>a</em> = <em>v</em>² / <em>R</em> = (2 m/s)² / (0.1 m) = 40 m/s²