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Alika [10]
3 years ago
5

Which of the following objects will have the greatest inertia?

Physics
1 answer:
max2010maxim [7]3 years ago
6 0

Answer:

The proximate answer pertaining to your question entails 10 kg.

Justification:

The statement implies which of the following units preceded by the value of 10 will obtain substantial inertia.

Exploiting conversions, this can be evinced/demonstrated:

Choice "10 m" => .01 kg

10 J ==> 0.10

10 N ==> 1.02 kg

10 kg  ==>  10 kg

Thus, an object obtaining a cumulative mass of 10 kg obtains substantial inertia.

<h3>*Hope this helps*</h3>
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A very long string (linear density 0.7 kg/m ) is stretched with a tension of 70 N . One end of the string oscillates up and down
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To develop this problem it is necessary to apply the concepts related to Wavelength, The relationship between speed, voltage and linear density as well as frequency. By definition the speed as a function of the tension and the linear density is given by

V = \sqrt{\frac{T}{\rho}}

Where,

T = Tension

\rho = Linear density

Our data are given by

Tension , T = 70 N

Linear density , \rho = 0.7 kg/m

Amplitude , A = 7 cm = 0.07 m

Period , t = 0.35 s

Replacing our values,

V = \sqrt{\frac{T}{\rho}}

V = \sqrt{\frac{70}{0.7}

V = 10m/s

Speed can also be expressed as

V = \lambda f

Re-arrange to find \lambda

\lambda = \frac{V}{f}

Where,

f = Frequency,

Which is also described in function of the Period as,

f = \frac{1}{T}

f = \frac{1}{0.35}

f = 2.86 Hz

Therefore replacing to find \lambda

\lambda = \frac{10}{2.86}

\lambda = 3.49m

Therefore the wavelength of the waves created in the string is 3.49m

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