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german
3 years ago
15

Could you explain to me how the soccer collects kinetic energy when its kicked?

Physics
1 answer:
aniked [119]3 years ago
8 0
FOR THAT YOU NEED TO UNDERSTAND WHAT ACTUALLY KINETIC ENERGY IS.
It is a form of energy which is caused due to motion, when the ball is kicked, it is send into motion thus it gains kinetic energy, how come energy came from ? as you have already read this ENERGY MASS CANT BE CREATED OR DESTROYED. In this scenario the energy is being transferred by the football player into the ball which appears as the kinetic energy of the ball... that's how it works
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What's the average speed of an object moving 3790 meters in 249 s.
NISA [10]

Heya!!

For calculate velocity, lets applicate formula

                                                 \boxed{d = v * t}

                                               <u>Δ   Being   Δ</u>

                                         d = Distance = 3790 m

                                             t = Time = 249 s

                                             v = Velocity = ?

⇒ Let's replace according the formula and clear "v":

\boxed{v= 3790\ m / 249\ s}

⇒ Resolving

\boxed{ v = 15,22 \ m/s }

Result:

The velocity is <u>15,22 meters per second.</u>

Good Luck!!

4 0
2 years ago
A 0.060 kg ball hits the ground with a speed of –32 m/s. The ball is in contact with the ground for 45 milliseconds and the grou
SCORPION-xisa [38]

Answer:

imma try and get it wrong

3 0
2 years ago
A dwarf planet discovered out beyond the orbit of Pluto is known to have an orbital period of 619.36 years. What is its average
Maksim231197 [3]

Answer: 72.66 AU=1.089(10)^{10} km

Explanation:

Let's begin by explaining that according to Kepler’s Third Law of Planetary motion “The square of the orbital period T of a planet is proportional to the cube of the semi-major axis a of its orbit”:

T^{2}\propto a^{3} (1)  

Now, if T is measured in years (Earth years), and a is measured in astronomical units (equivalent to the distance between the Sun and the Earth: 1AU=1.5(10)^{8}km), equation (1) becomes:  

T^{2}=a^{3} (2)  

So, knowing T=619.36 years and isolating a from (2) we have:  

a=\sqrt[3]{T^{2}} (3)  

a=\sqrt[3]{(619.36 years)^{2}} (4)  

Finally:

a=72.66 AU T his is the distance between the dwarf planet and the Sun in astronomical units

Converting this to kilometers, we have:

a=72.66 AU \frac{1.5(10)^{8}km}{1 AU}=1.089(10)^{10} km

4 0
3 years ago
What are the Rules of magnetism
Keith_Richards [23]

all the allials must be aligned in the same direction

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3 0
3 years ago
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Answer:

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7 0
3 years ago
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