If someone throws a 3 gram fry accelerating at 5 meter/second2, what is the fry’s force?
1 answer:
The net force on the fry is 0.015 N.
Explanation:
We can solve this problem by using Newton's second law of motion, which states that:
where
F is the net force acting on an object
m is the mass of the object
a is its acceleration
In this problem, we have a fry with mass
m = 3 g = 0.003 kg
And its acceleration is
Therefore, the net force acting on the fry is
Learn more about Newton's second law of motion:
#LearnwithBrainly
You might be interested in
(a) The skater covers a distance of S=50 m in a time of t=12.1 s, so its average speed is the ratio between the distance covered and the time taken:
(b) The initial speed of the skater is
while the final speed is
and the time taken to accelerate to this velocity is t=2 s, so the acceleration of the skater is given by
(c) The initial speed of the skater is
while the final speed is
since she comes to a stop. The distance covered is S=8 m, so we can use the following relationship to find the acceleration of the skater:
from which we find
where the negative sign means it is a deceleration.
(b) The initial speed of the skater is
while the final speed is
and the time taken to accelerate to this velocity is t=2 s, so the acceleration of the skater is given by
(c) The initial speed of the skater is
while the final speed is
since she comes to a stop. The distance covered is S=8 m, so we can use the following relationship to find the acceleration of the skater:
from which we find
where the negative sign means it is a deceleration.