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stepan [7]
3 years ago
7

On average, each person in the industrialized world is responsible for the emission of 10,000 kg of carbon dioxide () every year

. This includes that you generate directly, by burning fossil fuels to operate your car or your furnace, as well as generated on your behalf by electric generating stations and manufacturing plants. is a greenhouse gas that contributes to global warming. If you were to store your yearly emissions in a cube at STP, how long would each edge of the cube be?
Physics
1 answer:
frosja888 [35]3 years ago
7 0

Answer:

17.2 meters

Explanation:

Carbon dioxide (CO2) molecular mass is 44g/mol, then the number of moles of 10000kg carbon dioxide will be:

10,000kg * (1000g/kg)/  (44g/mol) = 227,272moles

The volume of gas in STP is 22.4 L/mol, then the volume of the carbon dioxide will be:

227,272 moles* 22.4L/mol= 5,090,909 L

One liter equal to 0.001 meter cubic. The formula for cube volume is side^{3\\}, if the volume is 5090909L then the side of the cube will be:

volume= side^{3\\}

5090909L * (0.001 m^{3\\}/L)= side^{3\\}

side= \sqrt[3]{5090.909}

side= 17.2m

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The temperature and pressure at the surface of Mars during a Martian spring day were determined to be -50 °C and 900 Pa, respect
Sidana [21]

Answer:

T = 273 + (-50) = 273 – 50 = 223 K

R = 188.82 J / kg K for CO2

Density (Martian Atmosphere) = P / RT = 900 / 188.92 x 223 = 900 / 42129.16 = 0.0213 kg / m^{3}

T = 273 +18 = 291 K, R = 287 J / kg k (for air) P = 101.6 k Pa = 101600 Pa

Density (Earth Atmosphere) = P / RT = 101600 / 287 x 291 = 1.216 kg / m^{3}

4 0
4 years ago
Read 2 more answers
If the amplitude of a sound wave is tripled, by what factor will the intensity increase?
Shtirlitz [24]

Answer:

By a factor 9

Explanation:

The intensity of a sound wave is proportional to the square of the amplitude of the wave:

I \propto A^2

where

I is the intensity

A is the amplitude of the wave

In this problem, the amplitude of the sound wave is increased by a factor 3:

A' = 3A

So the intensity would change by

I' \propto A'^2 = (3A)^2 = 9 A^2 = 9I

So, the intensity would increase by a factor 9.

5 0
3 years ago
You are riding on a carousel that is rotating at a constant 24 rpm. It has an inside radius of 4 ftand outside radius of 12 ft.
Nookie1986 [14]

Answer:

magnitude of the Coriolis acceleration is 44.235 ft/s² and the direction of the acceleration is along the axis of transmission

Explanation:

Given the data in the question;

Speed of carousel N = 24 rpm

From the diagram below, selected path direction defines the Axis of slip.

Hence, The Coriolis is acting along the axis of transmission

Now, we determine the angular speed ω of the carousel.

ω = 2πN / 60

we substitute in the value of N

ω = (2π × 24) / 60

ω = 2.5133 rad/s

Next, we convert the given velocity from mph to ft/s

we know that; 1 mph = 1.4667 ft/s

so

V_{slip = 6 mph = ( 6 × 1.4667 ) = 8.8002 ft/s

Now, we determine the magnitude of the Coriolis acceleration

a_c = 2( V_{slip × ω )

we substitute

a_c = 2( 8.8002 ft/s × 2.5133 rad/s )

a_c = 44.235 ft/s²

Hence, magnitude of the Coriolis acceleration is 44.235 ft/s² and the direction of the acceleration is along the axis of transmission

7 0
3 years ago
HELP ME DO THIS QUESTION PLEASE ​
raketka [301]

Answer:

i dont know

Explanation:

but what you can do is ask you mom or dad to get you a tutor to help you

7 0
3 years ago
The distance between the lenses in a compound microscope is 18 cm. The focal length of the objective is 1.5 cm. If the microscop
Blababa [14]

Answer:

The focal length of eye piece is 6.52 cm.

Explanation:

Given that,

Angular Magnification of the microscope M = -46

the distance between the lens in microscope L= 16 cm

The focal length of objective f₀ = 1.5 cm

Normal near point N = 25 cm

Have to find focal length of eye piece f ₙ =?

The angular magnification is given by

M ≈ - (L-fₙ)N/f₀fₙ

Rearranging for fₙ

fₙ =L(1 - Mf₀/N)⁺¹

   =18/2.76

fₙ =  6.52 cm

The focal length of eye piece is 6.52 cm.

6 0
4 years ago
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