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2 years ago

What is the key to being a good engineer?

Engineering

2 answers:

wariber [46]2 years ago

4 0

Answer:

Approaching a problem and finding a solution within given guidelines.

Explanation:

To be a good engineer, you simply need to know how to create a solution to a problem with a given set of restraints or guidelines.

For instance, let's say your boss wants you to build a machine that can automate some trivial task so he can use the worker elsewhere. He wants the machine to be low maintenance and under $40,000.

As an engineer, your first thought should be, let's see what this "trivial task" is, and then after your observation, you should begin to pull upon your experience and resources to build a solution that can be low maintenance and under $40,000.

Put simply, when you approach a problem, consider all aspects of the problem and then build a solution that satisfies all requirements.

Cheers.

padilas [110]2 years ago

3 0

Answer: ‍♀️

Explanation:

Many engineers focus their professional development efforts on improving their technical skills. Don't underestimate the importance of soft skills, however, such as communication, teamworking, and presentation skills. You should also take time to acquire and improve essential skills like these.

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The pressure distribution over a section of a two-dimensional wing at 4 degrees of incidence may be approximated as follows: Upp

Aliun [14]

Answer:

The lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

Explanation:

The Upper Surface Cp is given as

$Cp_u=-0.8 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.8*0.6+0.4*0.1$

The Lower Surface Cp is given as

$Cp_l=-0.4 *0.6 +0.1 \int\limits^1_{0.6} \, dx =-0.4*0.6+0.4*0.1$

The difference of the Cp over the airfoil is given as

$\Delta Cp=Cp_l-Cp_u\\\Delta Cp=-0.4*0.6+0.4*0.1-(-0.8*0.6-0.4*0.1)\\\Delta Cp=-0.4*0.6+0.4*0.1+0.8*0.6+0.4*0.1\\\Delta Cp=0.4*0.6+0.4*0.2\\\Delta Cp=0.32$

Now the Lift Coefficient is given as

$C_L=\Delta C_p cos(\alpha_i)\\C_L=0.32\times cos(4*\frac{\pi}{180})\\C_L=0.3192$

Now the coefficient of moment about the leading edge is given as

$C_M=-0.3*0.4*0.6-(0.6+\dfrac{0.4}{3})*0.2*0.4\\C_M=-0.1306$

So the lift coefficient is 0.3192 while that of the moment about the leading edge is-0.1306.

5 0

2 years ago

Which of the following is a advantage of a chain and sprocket over a pulley and belt system?

Tatiana [17]

Answer:

A) Cost

Explanation:

Chain drives have low maintenance cost.

3 0

2 years ago

In the construction of a timber-framed house, select and justify three timber based

kvasek [131]

Timber frame construction uses timber studs and rails, together with a structural sheathing board, to form a structural frame that transmits all vertical and horizontal loads to the foundations.

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2 years ago

Incremental software development could be very effectively used for customers who do not have a clear idea about the systems nee

avanturin [10]

<u>Software Development and Client Needs</u>

In Incremental method of software development customers who do not have a basic idea of the development process are being carried along on like other methods that will relegate them to the background until a product is ready.

With this model and structure in place, when softwares/ products are built from several stages e.g prototype, testing, and when new features are added customers are always carried along with their valuable feedback and suggested greatly considered to achieve the customers satisfactions

This model will work well for the customers/clients who does not have a clear idea on the systems needed for their operations.

In summary the incremental model combines features from the waterfall and prototyping model.

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2 years ago

Steam at 75 kPa and 8 percent quality is contained in a spring-loaded piston–cylinder device, as shown in Figure, with an initia

Rashid [163]

The heat transferred to and the work produced by the steam during this process is 13781.618 kJ/kg

<h3>How to calcultae the heat?</h3>

The Net Change in Enthalpy will be:

= m ( h2 - h1 ) = 11.216 ( 1755.405 - 566.78 ) = 13331.618 kJ/kg

Work Done (Area Under PV curve) = 1/2 x (P1 + P2) x ( V1 - V2)

= 1/2 x ( 75 + 225) x (5 - 2)

W = 450 KJ

From the First Law of Thermodynamics, Q = U + W

So, Heat Transfer = Change in Internal Energy + Work Done

= 13331.618 + 450

Q = 13781.618 kJ/kg

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6 0

1 year ago