Answer:
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Explanation:
Answer:
(a) 561.12 W/ m² (b) 196.39 MW
Explanation:
Solution
(a) Determine the energy and power of the wave per unit area
The energy per unit are of the wave is defined as:
E = 1 /16ρgH²
= 1/16 * 1025 kg/ m3* 9.81 m/s² * (2.5 m )²
=3927. 83 J/m²
Thus,
The power of the wave per unit area is,
P = E/ t
= 3927. 83 J/m² / 7 s = 561.12 W/ m²
(b) The average and work power output of a wave power plant
W = E * л * A
= 3927. 83 J/m² * 0.35 * 1 *10^6 m²
= 1374.74 MJ
Then,
The power produced by the wave for one km²
P = P * л * A
= 5612.12 W/m² * 0.35 * 1* 10^6 m²
=196.39 MW
Answer:
B. 26 rpm
Explanation:
The sprocket has a diameter of 10 in
The back wheel has a diameter of 6.5 in
One complete revolution formula is : 2πr -------where r is radius
For the sprocket , one revolution = π * D where D=2r
π * 10 = 31.4 in
For the back wheel, one revolution = π* 6.5 = 20.42 in
The pedaling rate is : 40 rpm
Finding the ratio of revolutions between the sprocket and the back tire.
In one revolution; the sprocket covers 31.4 in while the back tire covers 20.42 in so the ratio is;
20.42/ 31.4 = 0.65
So if the speed in the sprocket is 40 rpm then that in the back tire will be;
40 * 0.65 = 26 rpm