Question

The information on a can of pop indicates that the can contains 360 mL. The mass of a full can of pop is 0.369 kg, while an empty can weighs 0.153 N. Determine the specific weight, density, and specific gravity of the pop and compare your results with the corresponding values for water at 20° C. Express your results in SI units.

Answer 1

Answer

given,

volume of the can = 360 mL  = 360 x 10⁻⁶ m³

mass of the full can of pop = 0.369 kg

weight of the empty can = 0.153 N

temperature of water = 20⁰C

weight of the full can

 W = m g

 W = 0.369 x 9.8 = 3.616 N

Weight of the pop in can

w₂ = W - w₁

w₂ = 3.616 - 0.153

w₂ = 3.463 N

w₂ is weight of the liquid

Specific weight of the liquid

$\gamma = \dfrac{weight\ of\ liquid}{volume\ of\ liquid}$

$\gamma = \dfrac{3.463}{360\times 10^{-6}}$

$\gamma =9.6\times 10^3\ N/m^3$

density of liquid

$\rho = \dfrac{\gamma}{g}$

$\rho = \dfrac{9.6\times 10^3}{9.8}$

    ρ = 979.59 Kg/m³

specific gravity of the fluid

$SG = \dfrac{density\ of\ liquid}{density\ of\ water}$

$SG = \dfrac{979.59}{1000}$

   SG = 0.979

Specific gravity of pop is equal to 0.979