Answer:
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Answer:
a)
, b)
,
,
, c)
,
,
, 
Explanation:
a) The total number of users that can be accomodated in the system is:


b) The length of the side of each cell is:


Minimum time for traversing a cell is:



The maximum time for traversing a cell is:


The approximate time is giving by the average of minimum and maximum times:


c) The total number of users that can be accomodated in the system is:


The length of each side of the cell is:


Minimum time for traversing a cell is:



The maximum time for traversing a cell is:


The approximate time is giving by the average of minimum and maximum times:


Answer:
The flexural strength of a specimen is = 78.3 M pa
Explanation:
Given data
Height = depth = 5 mm
Width = 10 mm
Length L = 45 mm
Load = 290 N
The flexural strength of a specimen is given by


78.3 M pa
Therefore the flexural strength of a specimen is = 78.3 M pa