Answer:
In return mode, the system assists steering return after completing a turn. Information from the steering position sensor prevents the system from overshooting the center position. In dampener mode, the system acts like a hydraulic dampener to prevent kick back and bump steer.
Answer:
Explanation:
Given that
Shear modulus= G
Sectional area = A
Torsional load,
For the maximum value of internal torque
Therefore
Thus the maximum internal torque will be at x= 0.25 L
![t(x)_{max} = \int_{0}^{0.25L}p sin( \frac{2\pi}{ L} x)dx\\t(x)_{max} =\left [p\times \dfrac{-cos( \frac{2\pi}{ L} x)}{\frac{2\pi}{ L}} \right ]_0^{0.25L}\\t(x)_{max} =\dfrac{p\times L}{2\times \pi}](https://tex.z-dn.net/?f=t%28x%29_%7Bmax%7D%20%3D%20%5Cint_%7B0%7D%5E%7B0.25L%7Dp%20sin%28%20%5Cfrac%7B2%5Cpi%7D%7B%20L%7D%20x%29dx%5C%5Ct%28x%29_%7Bmax%7D%20%3D%5Cleft%20%5Bp%5Ctimes%20%5Cdfrac%7B-cos%28%20%5Cfrac%7B2%5Cpi%7D%7B%20L%7D%20x%29%7D%7B%5Cfrac%7B2%5Cpi%7D%7B%20L%7D%7D%20%20%5Cright%20%5D_0%5E%7B0.25L%7D%5C%5Ct%28x%29_%7Bmax%7D%20%3D%5Cdfrac%7Bp%5Ctimes%20L%7D%7B2%5Ctimes%20%5Cpi%7D)
Answer:
685.38 MJ
Explanation:
Given that:
mass = 10 tons = 1.0 × 10 ⁴ kg
diameter D = 10 m
radius R = 5 m
speed N = 1000 rpm
Using the formula for K.E = 
to calculate the energy stored
where;
= 104.719 rad/s
Hence, the energy stored is;
= 685379310.1
= 685.38 MJ
Answer:
331809.5gallon/hr or 92.16gallon/s
Explanation:
What is the peak runoff discharge for a 1.3 in/hr storm event from a 9.4-acre concrete-paved parking lot (C
convert 9.4 acre to inches we have=5.896*10^7
How to calculate Peak runoff discharge
1. take the dimension of the roof
2. multiply the dimension by the n umber of inches of rainfall
3. Divide by 231 to get gallon equivalence (because 1 gallon = 231 cubic inches)
5.896*10^7*1.3
7.66*10^7 cubic inches/hr
1 gallon=231 cubic inches
7.66*10^7 cubic inches=331809.5gallon/hr or 92.16gallon/s
this is gotten by converting 1 hr to seconds
331809.5gallon/hr /3600s=92.16gallon/s
