Answer:
7.94 ft^3/ s.
Explanation:
So, we are given that the '''model will be 1/6 scale (the modeled valve will be 1/6 the size of the prototype valve)'' and the prototype flow rate is to be 700 ft3 /s. Then, we are asked to look for or calculate or determine the value for the model flow rate.
Note that we are to use Reynolds scaling for the velocity as par the instruction from the question above.
Therefore; kp/ks = 1/6.
Hs= 700 ft3 /s and the formula for the Reynolds scaling => Hp/Hs = (kp/ks)^2.5.
Reynolds scaling==> Hp/ 700 = (1/6)^2.5.
= 7.94 ft^3/ s
Answer:
Tech B
Explanation:
Horsepower (hp) refers to a unit of measurement of power in respect of the output of engines or motors.
Horsepower is the common unit of power. It indicates the rate at which work is done.
The formula
, where rpm is the engine speed, T is the torque, and 5,252 is radians per second.
So,
Tech B is correct
Answer:
d. 2.3 ohms (5.3 amperes)
Explanation:
The calculator's 1/x key makes it convenient to calculate parallel resistance.
Req = 1/(1/4 +1/8 +1/16) = 1/(7/16) = 16/7 ≈ 2.3 ohms
This corresponds to answer choice D.
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<em>Additional comment</em>
This problem statement does not tell the applied voltage. The answer choices suggest that it is 12 V. If so, the current is 12/(16/7) = 21/4 = 5.25 amperes.
Answer:
The heater load =35 KJ/kg
Explanation:
Given that
At initial condition
Temperature= 15°C
RH=80%
At final condition
Temperature= 50°C
We know that in sensible heating process humidity ratio remain constant.
Now from chart
At temperature= 15°C and RH=80%
![h_1=38 \frac{KJ}{kg},v=0.8 \frac{m^3}{kg}](https://tex.z-dn.net/?f=h_1%3D38%20%5Cfrac%7BKJ%7D%7Bkg%7D%2Cv%3D0.8%20%5Cfrac%7Bm%5E3%7D%7Bkg%7D)
At temperature= 50°C
![h_2=73 \frac{KJ}{kg}](https://tex.z-dn.net/?f=h_2%3D73%20%5Cfrac%7BKJ%7D%7Bkg%7D)
![So\ the\ heater\ load =h_2-h_1](https://tex.z-dn.net/?f=So%5C%20the%5C%20heater%5C%20load%20%3Dh_2-h_1)
The heater load = 73 - 38 KJ/kg
The heater load =35 KJ/kg