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soldi70 [24.7K]
3 years ago
11

Which equation is equivalent to 2/3(3x+9)=21​

Mathematics
2 answers:
ivann1987 [24]3 years ago
7 0

Answer:

2x+6=21 is equal to your equation

Vladimir [108]3 years ago
3 0

Answer:

Z Nansen

Step-by-step explanation:

S sba

You might be interested in
Determine the value of the rest of the angles
Inessa [10]

Answer:

2, 5, 6 are all 154

1, 3, 4, and 7 are all 26

4 0
3 years ago
Can some one please help me
saw5 [17]

Basically, all you have to do is substitue the terms given at the top.

x = -3

y = 6

z = -4

<em>The first one will be set up like this:</em>

(-3) + 6 + (-1) = 2

<em>The second one will be set up like this: </em>

-15 + (- -3) + 6 = -6

<em>The third one will be set up like this:</em>

3(-3) - 2(6) + (-4) = -25

<em>The fourth one will be set up like this:</em>

2(-4) - 3 (6) + 4(-3) = -38

<em>The fifth one will be set up like this: </em>

3 ( -3) + 2 (6) + (-4) = -1

<em>The sixth will be set up like this: </em>

(-3)(-4)

---------- = -1

-2 (6)

<em>The seventh will be set up like this:</em>

2 (6) (-4) - 3 (-3) = -39

Hope this helps! Have a good day/night! c:

6 0
3 years ago
8) HELP PLEASE ILL GIVE BRAINLIEST!! Find the median of the set of data.(Remember to put the
crimeas [40]
The median is 7.

——————————

Arrange data in numerical order

1 3 3 6 8 10 10 15

Total number are 8, N = 8

Take the middle two numbers 6 and 8 and take their average

6+8/2 = 14/2 = 7

Therefore the median is 7.
3 0
2 years ago
Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth
taurus [48]

Answer:

So, solution of  the differential equation is

y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

We use the Method of Undetermined Coefficients.

We first solve the homogeneous differential equation y′′+4y=0.

y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\

It is a homogeneous solution:

y_h(t)=c_1e^{-2i t}+c_2e^{2i t}

Now, we finding a particular solution.

y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\

we get

y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

So, solution of  the differential equation is

y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

7 0
3 years ago
What are the coordinates of the vertex of the parabola described by the equation below? y = -7(x - 4)2 - 5
pochemuha
To get the vertex of the parabola we proceed as follows;
y=-7(x-4)^2-5
The above can be written as:
y=-7x^2+56x-117
The values of a,b and c are:
a=-7, b=56 and c=-117
x=-b/(2a)
x=-56/(-7*2)=4
but;
y=-7x^2+56x-117
y=-7(4)^2+56(4)-117
y=-5
Thus;
x=4 and y=-5
The vertex will be at point (4,-5)


7 0
3 years ago
Read 2 more answers
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