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Akimi4 [234]
2 years ago
15

1. Complete the balanced dissociation equation for the compound below. If the compound does not dissociate, write NR after the r

eaction arrow.
(NH4)2S(s) -> ______


2. Write the balanced NET ionic equation for the reaction when Al(NO₃)₃ and Na₃PO₄ are mixed in aqueous solution. If no reaction occurs, write only NR.
Chemistry
1 answer:
puteri [66]2 years ago
7 0

Answer:

1. (NH₄)₂S(s) -----> NH₄+(aq) + S²-(aq)

2. Al³+ (aq) + PO₄³+ (aq) ----> AlPO₄ (s)

Explanation:

The dissociation of ammonium sulphide, (NH₄)₂S when dissolved in water is given in the equation below:

(NH₄)₂S(s) -----> NH₄+(aq) + S²-(aq)

However very little S²- ions are present in solution due to the very basic nature of the S²- ion (Kb = 1 x 105).

The ammonium ion being a better proton donor than water, donates a proton to sulphide ion to form hydrosulphide ion which exists in equilibrium with aqueous ammonia.

S²- (aq) + NH₄+ (aq) ⇌ SH- (aq) + NH₃ (aq)

Aqueous solutions of ammonium sulfide are smelly due to the release of hydrogen sulfide and ammonia, hence, their use in making stink bombs.

2. The reaction between aluminium nitrate and sodium phosphatein aqueous solution is a double decomposition reaction whish results in the precipitation of insoluble aluminium phosphate. The equation of the reaction is given below :

Al(NO₃)₃ (aq) + Na₃PO₄ (aq) ----> AlPO₄ (s) + 3 NaNO₃ (aq)

The net ionic equation is given below:

Al³+ (aq) + PO₄³+ (aq) ----> AlPO₄ (s)

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iogann1982 [59]
1. True
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3 years ago
What determines the traits of offspring?A.Food sources that have been genetically engineered B.Literary metaphors and exciting c
iren2701 [21]

Answer:

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Explanation:

8 0
3 years ago
A 25.00 mL sample of vinegar was titrated with 39.27 mL of 0.4293 M NaOH. Calculate the concentration of acetic acid in the vine
QveST [7]

Answer:

0.6743 M

Explanation:

HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O

First we <u>calculate how many NaOH moles reacted</u>, using the <em>definition of molarity</em>:

  • Molarity = moles / volume
  • moles = Molarity * volume
  • 0.4293 M * 39.27 mL = 16.86 mmol NaOH

<em>One NaOH moles reacts with one acetic acid mole</em>, so <u>the vinegar sample contains 16.86 mmoles of acetic acid as well</u>.

Finally we <u>calculate the concentration (molarity) of acetic acid</u>:

  • 16.86 mmol HC₂H₃O₂ / 25.00 mL = 0.6743 M
4 0
3 years ago
Question 2
QveST [7]
Metals only and ionic
3 0
3 years ago
Read 2 more answers
The change in enthalpy is the change in heat energy of a reaction and is calculated by (Hint: Hess' Law): Group of answer choice
Stolb23 [73]

Answer:

d. Sum of product enthalpies minus the sum of reactant enthalpies

Explanation:

The standard enthalpy change of a reaction (ΔH°rxn) can be calculated using the following expression:

ΔH°rxn = ∑n(products) × ΔH°f(products) - ∑n(reactants) × ΔH°f(reactants)

where,

ni are the moles of products and reactants

ΔH°f(i) are the standard enthalpies of formation of products and reactants

8 0
3 years ago
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