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Brums [2.3K]
3 years ago
5

Why is rain likely when warm, moisture-laden air meets cold air? A) The lighter warm air will rise and cool down, causing conden

sation and rain. B) The cold air moves faster and pushes the warm air away, causing condensation and rain. Eliminate C) The moisture in the warm air condenses on contact with the cold air, causing rain to fall. D) The cold air mixes with the warm air, reducing its temperature causing moisture to condense.
Chemistry
2 answers:
DerKrebs [107]3 years ago
8 0

Answer:

B) The cold air moves faster and pushes the warm air away, causing condensation and rain.

notsponge [240]3 years ago
4 0
The answer is most likely B
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A 2.000 g sample of CoCl2.xH2O is dried in an oven. When the anhydrous salt is removed from the oven, its mass is 1.565 g. What
Mashutka [201]

The value of X is 2

The total amount of sample taken is 2.00 g

The amount of sample left in the oven after drying is 1.565g

The amount of sample lost (mass of water driven out) = Total sample-Anhydrous salt left in the oven

                                 = 2.00 - 1.565

                                = 0.435 grams

The moles of anhydrous salt present in the hydrate = 1.565g/129.83g/mol = 0.01205

The moles of water present in the hydrate = 0.4350g/18.01g/mol = 0.02415

Therefore the ratio of these two are in 1:2 ratio

The complete chemical reaction is   CoCl2.2H20

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brainly.com/question/14967837

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6 0
10 months ago
The number 0.000402 expressed in scientific notation is
goldfiish [28.3K]

Answer:

hope its help you

Explanation:

4.02 x 10-4

3 0
3 years ago
A 45-g aluminium spoon(specific heat 0.80 / J/gdegree Celsius) at 24 degree celsius is placed in 180 ml(180 grams) of coffee at
Vlad [161]

Explanation:

a) The amount of heat released by coffee will be absorbed by aluminium spoon.

Thus, heat_{absorbed}=heat_{released}

To calculate the amount of heat released or absorbed, we use the equation:  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

Also,

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]    ..........(1)

where,

q = heat absorbed or released

m_1 = mass of aluminium = 45 g

m_2 = mass of coffee = 180 g

T_{final} = final temperature = ?

T_1 = temperature of aluminium = 24^oC

T_2 = temperature of coffee = 85^oC

c_1 = specific heat of aluminium = 0.80J/g^oC

c_2 = specific heat of coffee= 4.186 J/g^oC

Putting all the values in equation 1, we get:

45 g\times 0.80J/g^oC\times (T_{final}-24^oC)=-[180 g\times 4.186J/g^oC\times (T_{final}-83^oC)]

T_{final}=80.30^oC

80.30 °C is the final temperature.

b) Energy flows from higher temperature to lower temperature.Whenever two bodies with different energies and temperature come in contact. And the resulting temperature of both bodies will less then the body with high temperature and will be more then the body with lower temperature.

So, is our final temperature of both aluminium and coffee that is 80°C less than initial temperature of coffee and more than the initial temperature of the aluminum.

8 0
2 years ago
A balanced chemical equation is shown below
IrinaVladis [17]

Answer:

The answer is A.

Explanation:

C6H12O6 + 6O2 -> 6CO2 + 6H20

C6H12O6 + 6O2 -> 6CO2 + 6H20At the reactant side, there are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms.

atoms, 12 hydrogen atoms and 18 oxygen atoms.At product side, there are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms.

(In a balanced equation, the no. of atoms on the reactant side must be <em><u>e</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>l</u></em><em> </em>to the no. of atoms on the product side)

4 0
3 years ago
M=10,V=2 What is the density
Sever21 [200]

Answer:

Density (ρ) = 5 kilogram/cubic meter

Explanation:

Steps:

ρ =  

m

V

=  

10 kilogram

2 cubic meter

=  5 kilogram/cubic meter

4 0
3 years ago
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