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Brums [2.3K]
3 years ago
5

Why is rain likely when warm, moisture-laden air meets cold air? A) The lighter warm air will rise and cool down, causing conden

sation and rain. B) The cold air moves faster and pushes the warm air away, causing condensation and rain. Eliminate C) The moisture in the warm air condenses on contact with the cold air, causing rain to fall. D) The cold air mixes with the warm air, reducing its temperature causing moisture to condense.
Chemistry
2 answers:
DerKrebs [107]3 years ago
8 0

Answer:

B) The cold air moves faster and pushes the warm air away, causing condensation and rain.

notsponge [240]3 years ago
4 0
The answer is most likely B
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How many moles are in 4.6 x 10^19 atoms? <br><br> *#27 is the question
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There are 0.000076 moles in 4.6 x 10^19 atoms.
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Ketones undergo a reduction when treated with sodium borohydride, NaBH4. The product of the above reaction has the following spe
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Answer:

The product is cyclohexanol

Explanation:

Firstly,

A ketone undergo a borohydride reduction reaction to form an alcohol as below,

R-CO-R'  ⇒ R-CO(OH)-R'

  1. IR Spectrum confirms that alcohol group is existed with the peak at 3400 cm⁻¹
  2. From 1H-NMR, the product has 10 hydrogen atoms, the MS suggest that the formula is C₅H₁₀O (M = 86). With this formula, the alcohol is monosaturated. Since, the substance already underwent reduction reaction, the only way to suggest a monosaturated compound is a cyclic alcohol. So the compound is cyclopentanol.
  3. Check with other spectroscopic properties,
  • 3 signals of 13C NMR confirms the structure is symmetrical, δ 24.2, (-<u>C</u>H₂-CH₂-CH(CH₂-)-OH), δ 35.5 (-CH₂-<u>C</u>H₂-CH(CH₂-)-OH), δ 73.3 (-CH₂-CH₂-<u>C</u>H(CH₂-)-OH).
  • 1H NMR confirms,

        1.56 δ (4H, triplet) - (-C<u>H</u>₂-CH₂-CH-OH) ; triplet as coupling with 2 H,

        1.78 δ (4H, multiplet)  - (-CH₂-C<u>H</u>₂-CH-OH); multiplet as coupling with 2H of CH₂, 1 H of CH

         3.24 δ (1H, quintet); - (-CH₂-CH₂-C<u>H</u>(CH₂-)-OH), coupling with4 H of 2 group of CH₂

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4 0
3 years ago
6. Three ice cubes are placed inside a glass of hot chocolate. Which of the following best
ycow [4]
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4 0
2 years ago
If a proton and an electron are released when they are 5.50×10−10 mm apart (typical atomic distances), find the initial accelera
Vlada [557]

Answer: The initial acceleration of the proton = (4.56 × 10^23) m/s2

The initial acceleration of the electron = (8.36 × 10^26) m/s2

Explanation: The force of attraction between the proton and electron can be computed using the statements of Coulomb's law which state that the force of attraction between two charged particles is directly proportional to the product of the two charges and inversely proportional to the square of their distances apart.

F = (Kq1q2)/(r^2) where K = (9 × (10^9) Nm(C^-2))

But q1 is the charge on a proton = (1.6 × (10^-19)) C

q2 is charge on an electron = -(1.6 × (10^-19)) C

r = (5.50 × (10^-10))mm = (5.50 × (10^-13))m

Computing all that, F = 0.0007616529 N = (7.62 × 10^-4) N

But the force of attraction is converted to that required for motion when they're released.

F = ma.

For proton, m = (1.67 × 10^-27) kg

a = F/m = 0.000762/(1.67 × 10^-27) = (4.56 × 10^23) m/s2

For electron, m = (9.11 × 10^-31) kg

a = F/m = 0.000762/(9.11 × 10^-31) = (8.36 × 10^26) m/s2

QED!

7 0
3 years ago
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