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Brums [2.3K]
4 years ago
5

Why is rain likely when warm, moisture-laden air meets cold air? A) The lighter warm air will rise and cool down, causing conden

sation and rain. B) The cold air moves faster and pushes the warm air away, causing condensation and rain. Eliminate C) The moisture in the warm air condenses on contact with the cold air, causing rain to fall. D) The cold air mixes with the warm air, reducing its temperature causing moisture to condense.
Chemistry
2 answers:
DerKrebs [107]4 years ago
8 0

Answer:

B) The cold air moves faster and pushes the warm air away, causing condensation and rain.

notsponge [240]4 years ago
4 0
The answer is most likely B
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Radon gas has a temperature of 24.5 c at 1087 torr pressure .what will the temperature be at 1 atm pressure
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Answer:

564.980

Explanation:

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What is occurring with the velocity between points D and E?
vichka [17]

Answer:

a

Explanation:

the line is going down

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3 years ago
Classify the four reactions that your group analyzed today as being either endothermic or exothermic
ArbitrLikvidat [17]
Chemical reactions are basically divided into two major classes depending on whether the reaction lose energy or gain energy from the environment during the course of the reaction. The two classes of reaction are exothermic and endothermic reaction.
An exothermic reaction is a type of reaction in which the reaction system lose energy to the environment and thus, the energy content of the reactants is more than that of the product formed. Because of this, the enthapyl change of an exothermic reaction is always negative. 
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4 0
3 years ago
15. Within a voltaic cell,___
kobusy [5.1K]

Answer:

B. oxidation; reduction

Explanation:

A voltaic cell is electro-chemical cell in which chemical energy is converted into electrical energy.

1. This cell utilizes chemical reaction to generate electric.\

2. there two electrode anode and cathode

3. At Anode oxidation occurs

4. At cathode reduction occurs

5. chemical is present in the cell which is electrolyte which completes the circuit of the voltaic cell.

  • oxidation is the process in which there is loss of electrons
  • Reduction is the process in which there is gain of electrons

___________________________________________________

Based on above discussion

At anode oxidation takes place

At cathode reduction takes place.

Hence, correct option is B. oxidation; reduction

7 0
3 years ago
Which of the following (with specific heat capacity provided) would show the smallest temperature change upon gaining 200.0 J of
Brut [27]

<u>Answer:</u> The smallest temperature change is shown by water.

<u>Explanation:</u>

To calculate the heat absorbed or released, we use the equation:

q=mC\times \Delta T      ......(1)

where,

q = heat absorbed = 200.0 J

m = mass of the substance

C = specific heat of substance

\Delta T = change in temperature

As, the same amount of heat is getting absorbed in all the cases. So, the change in temperature will depend on the product of mass and specific heat.

For the given options:

  • <u>Option a:</u>  50.0 g Fe, C_{Fe}=0.449J/g^oC

We are given:

m=50.0g\\C_{Fe}=0.449J/g^oC

Putting values in equation 1, we get:

200.0J=50.0g\times 0.449J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{50\times 0.449}=8.99^oC

Change in temperature = 8.99°C

  • <u>Option b:</u>  50.0 g water, C_{water}=4.18J/g^oC

We are given:

m=50.0g\\C_{water}=4.18J/g^oC

Putting values in equation 1, we get:

200.0J=50.0g\times 4.18J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{50\times 4.18}=0.96^oC

Change in temperature = 0.96°C

  • <u>Option b:</u>  25.0 g Pb, C_{Pb}=0.128J/g^oC

We are given:

m=50.0g\\C_{Pb}=0.128J/g^oC

Putting values in equation 1, we get:

200.0J=25.0g\times 0.128J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.128}=62.5^oC

Change in temperature = 62.5°C

  • <u>Option d:</u>  25.0 g Ag, C_{Ag}=0.235J/g^oC

We are given:

m=25.0g\\C_{Ag}=0.235J/g^oC

Putting values in equation 1, we get:

200.0J=25.0g\times 0.235J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.235}=34.04^oC

Change in temperature = 34.04°C

  • <u>Option e:</u>  25.0 g granite, C_{granite}=0.79J/g^oC

We are given:

m=25.0g\\C_{Fe}=0.79J/g^oC

Putting values in equation 1, we get:

200.0J=25.0g\times 0.79J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.79}=10.13^oC

Change in temperature = 10.13°C

Hence, the smallest temperature change is shown by water.

5 0
3 years ago
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