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densk [106]
3 years ago
7

Which group of elements will readily lose one electron to meet the octet rule? Alkaline Earth Metals c. Halogens Alkali Metals d

. Both A and B
Chemistry
1 answer:
vova2212 [387]3 years ago
4 0

Answer:

Alkali metals

Explanation:

The alkali metals are a group of metallic elements which are present in the first group of the periodic table. In other words, they are present in group 1 of the periodic table. These elements have one electron in their valence shell, the reason why they are placed in group 1.

They ionize by losing one electron to achieve the configuration of the nearest Noble gas or inert gas. Because they need to offset only one electron in their outermost shell, they are very chemically reactive and hence rarely occur in the free state.

Examples of elements in this group include lithium, potassium and sodium. They each have one electron only in their outermost shells.

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2. How many moles of copper are needed to react with sulfur to produce 0.25 moles of
dimaraw [331]

Answer:

0.5

Explanation:

Cu       Cu2S

2   :       1 ratio

therefore  0.25 moles of Cu2S * (2 moles of Cu/ 1 mole of Cu2S)

=0.5 moles of Cu

6 0
4 years ago
Do you think sugar would be soluble in hexane based on its structure
Fittoniya [83]

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The dipole forces (particularly H-bonds) that keep polar solute molecules together can be replaced by polar solute-solvent interactions, so substances that are predominantly polar (like glucose) dissolve in polar solvents like water but not in nonpolar solvents like hexane (H-bonds).

Explanation:

5 0
3 years ago
Which of the following is not one of the three common forms of matter
Gnesinka [82]

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Plasma.

Explanation:

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3 0
3 years ago
All rocks began as what type of rock?<br> planetary<br> igneous<br> metamorphic<br> sedimentary
zlopas [31]

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3 0
3 years ago
a 3.81 g sample of NaHCO3 was completely decomposed. After decomposition, Na2CO3 had mass of 2.86g. Determine mass of H2CO3 prod
qaws [65]

Answer:

1.67g H2CO3 are produced

Explanation:

Based on the reaction:

2NaHCO3 → Na2CO3 + H2CO3

<em>2 moles of NaHCO3 produce 1 mole of Na2CO3 and 1 mole of H2CO3</em>

To solve this question we need to find the moles of Na2CO3 = Moles of H2CO3. With their moles we can find the mass of H2CO3 as follows:

<em>Moles Na2CO3 -Molar mass: 105.99g/mol-</em>

2.86g Na2CO3 * (1mol/105.99g) = 0.02698 moles Na2CO3 = Moles H2CO3

<em>Mass H2CO3 -Molar mass: 62.03g/mol-</em>

0.02698 moles  * (62.03g/mol) =

<h3>1.67g H2CO3 are produced</h3>

8 0
3 years ago
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