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Gre4nikov [31]
3 years ago
5

Given the reaction system in a closed container at equilibrium and at a temperature of 298 K:

Chemistry
2 answers:
Tomtit [17]3 years ago
7 0
Constant. The concentrations must be constant and the rates must be equal.
MAVERICK [17]3 years ago
4 0

Answer:

The measurable quantities of the gases at equilibrium must be constant

Explanation:

Measurable quantities for the gases at equilibrium includes rate of formation of NO_{2}, rate of formation of N_{2}O_{4}, pressure of NO_{2} and pressure of N_{2}O_{4}.

At equilibrium, rate of forward reaction is equal to rate of reverse reaction.

Rate of forward reaction infers rate of formation of NO_{2} and rate of backward reaction infers rate of formation of N_{2}O_{4}.

As rate of formations from both direction are equal therefore pressure of both gaseous species remains constant.

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When a glucose molecule loses a hydrogen atom as the result of an oxidation-reduction reaction in glycolysis, the glucose is?
maria [59]
Reduced- in a way losing an H means gaining an e-
7 0
2 years ago
In a separate experiment beginning from the same initial conditions, including a temperature Ti of 25.0°C, half the number of mo
NNADVOKAT [17]

Answer:

- 178 ºC

Explanation:

The  ideal gas law   states that :

PV = nRT,

where P is the pressure, V is the volume, n is number of moles , R is the gas constant and T is the absolute temperature.

For the initial conditions :

P₁ V₁ = n₁ R T₁    (1)

and for the final conditions:

P₂V₂= n₂ R T₂    where   n₂ = n₁/2     then    P₂ V₂ = n₁/2 T₂    (2)

Assuming V₂ = V₁ and  dividing (2) by Eqn (1) :

P₂ V₂ = n₁/2 R T₂  / ( n₁ R T₁)      then  P₂ / P₁ = 1/2 T₂ / T₁

4.10 atm / 25.7 atm = 1/2 T₂ / 298 K ⇒ T₂ = 0.16 x 298 x 2 = 95.1 K

T₂ = 95 - 273 = - 178 º C

6 0
3 years ago
A sample of an ideal gas at 1.00 atm and a volume of 1.87 L was placed in a weighted balloon and dropped into the ocean. As the
Ludmilka [50]

Answer:

Volume of sample after droping into the ocean=0.0234L

Explanation:

As given in the question that gas is idealso we can use ideal gas equation to solve this;

Assuming that temperature is constant;

Lets P_1 and V_1 are the initial gas parameter before dropping into the ocean

and P_2 and V_2 are the final gas parameter after dropping into the ocean

according to boyle 's law pressure is inversly proportional to the volume at constant temperature.

hence,

P_1V_1=P_2V_2

P1=1 atm

V1=1.87L

P2=80atm

V2=?

After putting all values we get;

V2=0.0234L

Volume of sample after droping into the ocean=0.0234L

7 0
3 years ago
The picture below shows Enchanted Rock, a pink granite rock formation located in the Llano Uplift ecoregion. This land is most l
Katyanochek1 [597]

Answer:

what are the answers?

Explanation:

Probably going to be c for this, until the answers you choose are shown. very very sorry :c

5 0
2 years ago
A container holds 15.0 g of phosphorous gas at a pressure of 2.0 atm and a temperature of 20.0 Celsius. What is the density of t
erik [133]
<span>Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We calculate as follows:

PV = nRT
PV = mRT/ Molar mass
m/V = P(molar mass)/RT
Density = P(molar mass)/RT 
Density = 2.0 ( 30.97 ) / 0.08206 ( 20 + 273.15) = 2.57 g/L <----First option</span>
5 0
3 years ago
Read 2 more answers
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