Answer:
![f=5.76\times 10^{14}\ Hz](https://tex.z-dn.net/?f=f%3D5.76%5Ctimes%2010%5E%7B14%7D%5C%20Hz)
Explanation:
We need to find the frequency of green light having wavelength o
. It can be calculated as follows :
![c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{5.2\times 10^{-7}}\\\\f=5.76\times 10^{14}\ Hz](https://tex.z-dn.net/?f=c%3Df%5Clambda%5C%5C%5C%5Cf%3D%5Cdfrac%7Bc%7D%7B%5Clambda%7D%5C%5C%5C%5Cf%3D%5Cdfrac%7B3%5Ctimes%2010%5E8%7D%7B5.2%5Ctimes%2010%5E%7B-7%7D%7D%5C%5C%5C%5Cf%3D5.76%5Ctimes%2010%5E%7B14%7D%5C%20Hz)
So, the required frequency of green light is equal to
.
1 atm corresponds to 760 mmHg, so we can set up a simple proportion to find how many atmospheres correspond to 570 mmHg:
![1 atm: 760 mmHg = x: 570 mmHg](https://tex.z-dn.net/?f=1%20atm%3A%20760%20mmHg%20%3D%20x%3A%20570%20mmHg)
and from this, we find
Answer:
magnitude of the frictional torque is 0.11 Nm
Explanation:
Moment of inertia I = 0.33 kg⋅m2
Initial angular velocity w° = 0.69 rev/s = 2 x 3.142 x 0.69 = 4.34 rad/s
Final angular velocity w = 0 (since it stops)
Time t = 13 secs
Using w = w° + §t
Where § is angular acceleration
O = 4.34 + 13§
§ = -4.34/13 = -0.33 rad/s2
The negative sign implies it's a negative acceleration.
Frictional torque that brought it to rest must be equal to the original torque.
Torqu = I x §
T = 0.33 x 0.33 = 0.11 Nm