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Ilia_Sergeevich [38]
3 years ago
8

Which disease or disorder affects the lower respiratory system? Tuberculosis, laryngitis, sinus-itis, the common cold.

Physics
2 answers:
Wewaii [24]3 years ago
8 0

Answer:

Tuberculosis

Explanation:

Tuberculosis is a disease of lower respiratory system because it's affect the lungs and the voice box . It is a bacteria disease that affect the lungs and it is very contagious. It can spread rapidly to the brain and spine. Most times people with tuberculosis did not show symptoms but when there is symptoms,the symptoms include cough with blood, night sweats, fever e t.c.

Vlada [557]3 years ago
4 0

Answer:A

Explanation:

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Rudik [331]
Ok


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6 0
3 years ago
A 1.00 kg object moving in the + x direction at 10.0 m/s collides with a 1.50 kg object traveling at 5.00 m/s in the - x directi
marysya [2.9K]

Answer:

The amount of kinetic energy lost during the collision is 60.75 J

Explanation:

The given parameters are;

The mass of the object moving in the +x direction, m₁ = 1.00 kg

The velocity of the object moving in the +x direction, v₁ = 10.0 m/s

The mass of the object moving in the -x direction, m₂ = 1.50 kg

The velocity of the object moving in the +x direction, v₂ = 5.00 m/s

The final velocity of the 1.00 kg mass after collision, v₃ = 4.00 m/s

The direction of motion of the 1.00 kg mass after collision = -x direction

The total initial kinetic energy of the system, K.E._{total \ initial} = 1/2·m₁·v₁² + 1/2·m₂·v₂²

∴ K.E._{total \ initial}  = 1/2×1.00×10² + 1/2×1.50×5² = 68.75 J

The final kinetic energy of the system, K.E._{final}  = 1/2·m₁·v₃²

K.E._{final} = 1/2×1.00×4² = 8 J

The amount of kinetic energy lost during the collision, \Delta K.E._{system} is given as follows;

\Delta K.E._{system} =  K.E._{final} -K.E._{total \ initial} = 8 J - 68.75 J = -60.75 J

The amount of kinetic energy lost during the collision = 60.75 J.

7 0
3 years ago
he drag characteristics of a torpedo are to be studied in a water tunnel using a 1 : 7 scale model. The tunnel operates with fre
dusya [7]

Answer:20.03 m/s

Explanation:

Given

L_r=1:7

velocity of Prototype v_p=53 m/s

Taking Froude number same for both flow as it is a dimensionless number for different flow regimes in open Flow

(\frac{v_m}{\sqrt{L_mg}})=(\frac{v_p}{\sqrt{L_pg}})

v_m=v_p\times \sqrt{\frac{L_m}{L_p}}

v_m=53\times \frac{1}{\sqrt{7}}

v_m=20.03 m/s

           

4 0
3 years ago
Is my answer correct plz explain i don't understand it.
lora16 [44]

Answer:

yes that is correct

Explanation:

4 0
3 years ago
Q2: (2 marks) (show your work)
vfiekz [6]

Answer:

Net force = the difference between the forces of two directions

Net force= 60N-(30N+20N)

=60-50

Therefore Net force = 10N

6 0
3 years ago
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