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Levart [38]
2 years ago
7

Find the magnitude of the buoyant force on the block. The acceleration of gravity is 9.8 m/s 2 . Answer in units of N.

Physics
1 answer:
harkovskaia [24]2 years ago
6 0
The answer is 2248.02 N.
You might be interested in
A (nonconstant) harmonic function takes its maximum value and its minimum value
AURORKA [14]

Answer:

Explanation:

Consider that F (any function) <0 .

u(x,y) is a coontinuous function in the closed interval or region R.

Let us consider a point (p,q) that is inside the region and it is a maximum point.

Then it should be must

uxx (p,q) <0 where uxx means double differentiation

and uy(p,q) >0

Since ux(p,q) = 0 = uy(p,q) where ux and uy means single differentiation with respect to x and y respectively.

Say, Maximum limits of the region is T

therefore q<T

then uy (p,q) = 0 if q<T

if q = T then

point (p,q) = (p,T) will be on the boundary of R then we claim that

uy(p,q) >0

Similarly for the minimum also it will work

3 0
3 years ago
Pace left home at 8 AM to spend the day at an amusement park. He arrived at the park, which was 150 km from his house, at 10 AM.
arsen [322]

Answer:

average speed, accelerated speed

Explanation:

Pace was first moving at 38 km/h which was his average speed but the fastest speed he went was 60 km/h so he accelerated.

3 0
3 years ago
A force of 10 N causes a spring to extend by 20 mm. Find: a) the spring constant of the spring in N/m​
Mars2501 [29]

Answer:

formula used K=F/∆l

∆l is the elongation of the spring

  1. F=10N
  2. ∆l=20mm===> 0.02m
  3. K=10N divided 0.02m= 500N/m
6 0
2 years ago
during a workout, a football player pushes a blocking dummy a distance of 30 m. while pushing the dummy the same distance a seco
babymother [125]
Power=\frac{Work}{Time}=\frac{Force\times distance}{time}

If he wants to increase power, force must increase and decrease time.
8 0
3 years ago
Read 2 more answers
A block of weight 1200N is on an incline plane of 30° with the horizontal, a force P is applied to the body parallel to the plan
pshichka [43]

Answer:

a)  P = 807.85 N,  b)  P = 392.15 N,  c)  P = 444.12 N

Explanation:

For this exercise, let's use Newton's second law, let's set a reference frame with the x-axis parallel to the plane and the direction rising as positive, and the y-axis perpendicular to the plane.

Let's use trigonometry to break down the weight

         sin θ = Wₓ / W

         cos θ = W_y / W

         Wₓ = W sin θ

         W_y = W cos θ

         Wₓ = 1200 sin 30 = 600 N

          W_y = 1200 cos 30 = 1039.23 N

Y axis  

      N- W_y = 0

      N = W_y = 1039.23 N

Remember that the friction force always opposes the movement

a) in this case, the system will begin to move upwards, which is why friction is static

       P -Wₓ -fr = 0

       P = Wₓ + fr

as the system is moving the friction coefficient is dynamic

      fr = μ N

      fr = 0.20 1039.23

      fr = 207.85 N

we substitute

       P = 600+ 207.85

       P = 807.85 N

b) to avoid downward movement implies that the system is stopped, therefore the friction coefficient is static

        P + fr -Wx = 0

       fr = μ N

       fr = 0.20 1039.23

        fr = 207.85 N

we substitute

        P =  Wₓ -fr

        P = 600 - 207,846

        P = 392.15 N

c) as the movement is continuous, the friction coefficient is dynamic

         P - Wₓ + fr = 0

         P = Wₓ - fr

         fr = 0.15 1039.23

         fr = 155.88 N

         P = 600 - 155.88

         P = 444.12 N

6 0
2 years ago
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