Answer:
21.9g
Explanation:
This is the answer if you are on edginuity,
5.7% KCl is 94.3 % water.
Therefore, for 1000 g of water the mass of KCl will be (1000× 5.7)/94.3 = 60.445 grams.
1 mole of KCl is equal to 74.55 g,
therefore, 60.445 g will be 60.445/74.55 = 0.8108 mole of KCl
Hence, 0.8108 moles of KCl should release twice that number of moles 1.6216 moles ions.
Having 1.6216 moles of KCl ions dissolved in 1000g of water, gives us 1.6216 molar if solution.
Using the freezing point depression constant of water.
dT = Kf (molarity)
dT = (1.86 C/ molar) (1.6216 m)
dT = 3.016 C drop in freezing point
Therefore, it should freeze at - 3.016 Celsius
Answer:
The correct answer is b types of glycosidic bond between the monomers.
Explanation:
HomoPolysaccharides differ from each other by the presence of different glycosidic linkage within their chemical structure.
For example
1 Starch contain glucose residues which are linked by alpha-1,4-glycosidic linkage.
2 In glycogen molecule the glucose residues are linked together by both alpha-1,4-glycosidic linkage and alpha-1,6- glycosidic linkage.
3 In cellulose the glucose monomers are linked together by beta-1,4-glycosidic linkage.
Honestly just look at the question deeper and find it inside the equation of the fraction
N2O = 28 + 16 = 44g
number of moles
= given mass/molar mass
= 0.173/44
= 0.0039318