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pav-90 [236]
3 years ago
11

The equation, 2 H2(g) + O2(g) Imported Asset 2 H2O(l), represents an equation for a standard formation reaction.

Chemistry
2 answers:
disa [49]3 years ago
6 0

Answer : The given statement is false.

Explanation :

The given chemical reaction of formation of H_2O is:

2H_2(g)+O_2(g)\rightarrow 2H_2O(l)

Standard formation reaction :

In the standard formation reaction, one mole of substance always produced from its element that are present in their standard states.

Thus, the standard formation reaction of H_2O will be:

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)

Hence, the given statement is false.

VLD [36.1K]3 years ago
5 0
If this is asking if the equation is balanced, than the answer is true
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The following are electronegativity. What value should be where the M is?0.981.57M2.553.043.443.98No data
ipn [44]

Answer 2.04

Explanation

Electronegativity decreases down the group and increases across the period in the periodic table.

In the period two of the periodic table,we have the following values for electronegativities with respect to its elements.

Li...........0.98

Be.........1.57

B..........2.04

C.........2.55

N..........3.04

O...........3.44

F...........3.98

Ne........n.a

The value that should be where M is is 2.04

6 0
1 year ago
Why is the brcl molecule polar? the shared electrons are closer to cl due to the greater electronegativity of chlorine. bromine
klio [65]
The shared electrons are closer to Cl due to the greater electronegativity of chlorine.
8 0
3 years ago
Read 2 more answers
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Allisa [31]

Answer:

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Explanation:

3 0
3 years ago
"Inert" xenon actually forms many compounds, especially with highly electronegative fluorine. The ΔH° values for xenon difluorid
svp [43]

The average bond energy of the Xe¬F bonds in each fluoride is 132kJ/mol.

Given:

ΔH° of xenon difluoride (XeF2) = -105 kJ/mol

ΔH° of xenon tetrafluoride (XeF4)= -284 kJ/mol

ΔH° of xenon hexafluoride (XeF6) = -402 kJ/mol

The bond energy of Xe-F in XeF2 can be calculated as follows,

As we know that

ΔH° = ΔH°(bond formed) + ΔH°(bond broken)

The chemical reaction for the formation of XeF2 can be written in such a way,

Xe (g) + F2 (g) → XeF2 (g)

= [1 mol F2 (159 kJ/mol)] + [2(-Xe-F)] - 105 kJ/mol

= 159 kJ/mol + 2(-Xe-F) - 264 kJ/mol

= 2(-Xe-F)

Xe-F = 132 kJ/mol

Thus, we concluded that the average bond energy of the Xe¬F bonds in each fluoride is 132kJ/mol.

learn more about bond energy:

brainly.com/question/11653058

#SPJ4

3 0
1 year ago
A student drew a diagram of the quantum model of an atom, as shown. A small circle is shown. Six light gray spheres and six dark
Rufina [12.5K]

Answer:

The diagram is incorrect because there is only a single type of particle at the center of the atom.

Explanation:

The small circle at the centre of the sphere which contains six light gray spheres and six dark gray spheres represents the nucleus of the atom which is found at the centre of the atom.

The nucleus contains only one type of particle which is the proton. Hence the representation of two particles at the centre of the circle makes the model incorrect.

8 0
3 years ago
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