Answer:
It is the same reason that the distance by road is not the same as the distance "as the crow flies." The two vectors are often not aligned so that the magnitudes both add to directly to the distance from the origin (or the tail of the first vector).
For example, suppose you walk two segments of 1 mile each. If you walk east in both cases, you end up 2 miles east of where you started. (The sum of the vectors is the sum of their magnitudes.)
If you walk east 1 mile and north 1 mile, you end up about 1.4 miles from where you started, not 2 miles. The second "vector" did not add directly to the distance from your starting point.
If you walk east 1 mile, then west 1 mile, you end up exactly where you started. The sum of the vectors is zero, but the sum of their magnitudes is still 2 miles.
Explanation:
Explanation:
The attached figure shows the whole description.
Fraction covered in south,
Fraction covered in east,
Fraction covered in south,
MNO is a right angle triangle.
So,
AM = 1.24 miles
So, he is 1.24 miles from his starting point. Hence, this is the required solution.
Answer:
(D) 96 kg-m/s
Explanation:
Let's start off by first calculating the normal force between the box and the floor.
This will be:
Normal Force = 12 * 9.81 = 117.72 N
We can now use the friction equation to find the frictional force on the box when it is moving:
Frictional force = Coefficient of friction * Normal Force
Frictional force = 0.4 * 117.72 = 47.09 N
Finally, since we have the force on the box, we can find the acceleration:
F = Mass * Acceleration
47.09 = 12 * Acceleration
Acceleration = 3.92 m/s^2
Final speed after 2 seconds:
V= -3.84 m/s
Since we know the initial and final speeds, we can calculate the change in momentum:
Change in momentum = Final Momentum - Initial Momentum
Change in momentum =
Change in momentum = 94.08 kg*m/s
Thus we can see that option (D) is the closest answer.
Answer:
What soil conditions favor the use of belled caissons?
Answer:
- where the bell can be unearthed from a solid surface.
- where the supporting stratum below the bottom of the caisson is impermeable to water movement.
What soil conditions favor piles over caissons?
Answer:
- non-cosheal soils
- subterranean water or excessive depth of bearing strata make caisson unworkable
What type of piles are especially well suited to repair or improvement of existing foundations ?
Answer:
Without hammering, minipiles or helical piles are placed which escapes much of the vibration and noise associated with traditional pile installation. for working close to existing buildings or for improving the exiting foundations where excessive vibration could damage exiting structures or noise may interfere with ongoing activities these piles are good options.
Why?
Their slenderness involves little or no displacement of the soil, thus minimizing the risk of disturbance to nearby foundations.
List and explain some cost thresholds frequently encountered in foundation design.
Answer:
building below the water table- site dewatering must occur, strengthening of slopes supper system must be done and waterproofing of the foundation all of which entails money
building near existing building - this requires underpinning(The process of reinforcing the base of an existing building or other structure underpins it.)
increase in column/wall load- building height determines the foundation depth
Answer:
The ability of our bodies to adapt to different levels of gravity. You would become weaker and your heart is use to zero gravity. Boredom because there isn't much to in space. When intelligent people get bored, it's not pretty all the time...