<span>Draw the Lewis structure. Bromine has 3 bonds and two lone pairs for a trigonal bipyramidal electron geometry and an sp^3d hybridization. Fluorine is peripheral it does not require hybridization, but we often consider it to be hybridized too - it has 1 bond and 3 lone pairs for sp^3 hybridization. So the sigma bonds come from an overlap of an sp^3d orbital on Br with an sp^3 orbital on F. If you don't consider the F to be hybridized the overlap would have to be to a p orbital on the F</span>
The structures shown are examples of Constitutional Isomer.
In Chemistry, an isomer refers to a molecule that is similar to another but has differences. These differences can be:
- A difference in the constitution: The molecules have the same formula but the connectivities between elements or arrangement is different.
- Arrangement in space: The molecules have the same formula and connectivity, but they look different to do an arrangement in space of a position.
The molecules shown have the same formula because the elements in each pair are the same. However, the way these elements are connected is slightly different because the Br and the CH3 are connected to different carbons.
Based on this, the difference is the connectivity or constitution, and therefore these are constitutional isomers.
Learn more in: brainly.com/question/17125223
Answer:
CCl4 - Nonpolar
CH3OH - polar
NH3 - polar
CS2 - Nonpolar
Explanation:
One important thing that we should know is that polarity has to do with the presence of a resultant dipole moment in a molecule.
Dipole moment is a vector quantity, This means that its direction is also taken into account when discussing the dipole moment of molecules.
Hence, symmetrical molecules such as CS2 and CCl4 are non-polar even though they have polar bonds because their dipoles cancel out(zero resultant dipole moment).
On the other hand, NH3 and CH3OH are non-symmetrical molecules hence they possess an overall dipole moment and are polar molecules.
Answer:
Percent yield = 94.62%
Explanation:
Given data:
Actual yield of BeBr₂ = 1.23 mol
Theoretical yield of BeBr₂ = 220 g
Percent yield = ?
Solution:
Theoretical yield in moles:
Number of moles = mass/molar mass
Number of moles = 220 g/168.82 g/mol
Number of moles = 1.30 mol
Percent yield:
Percent tiled = actual yield / theoretical yield × 100
by putting values,
Percent yield = 1.23 mol / 1.30 mol × 100
Percent yield = 0.9462 × 100
Percent yield = 94.62%
