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zaharov [31]
4 years ago
14

How many moles of NaCI are in 250.0 ml of a 0.35 M NaCl solution?

Chemistry
1 answer:
AnnZ [28]4 years ago
6 0

<u>Answer:</u> The number of moles of NaCl in the solution are 0.0875 moles.

<u>Explanation:</u>

To calculate the number of moles of NaCl, we use the equation that is used to calculate molarity, which is:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

We are given:

Molarity of NaCl solution = 0.35 mol/L

Volume of solution = 250 mL = 0.250 L      (Conversion factor:  1L = 1000 mL)

Putting values in above equation, we get:

0.35mol/L=\frac{\text{Moles of NaCl}}{0.250L}\\\\\text{Moles of NaCl}=0.0875mol

Hence, the number of moles of NaCl in the solution are 0.0875 moles.

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Nicotine is 74.1% carbon, 8.6% hydrogen, and 17.3% nitrogen by mass. What is its molecular formula if its molar mass is 162.26 g
WINSTONCH [101]

first we need to find the empirical formula of nicotine

empirical formula is the simplest ratio of whole numbers of elements making up a compound

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masses of elements and the number of moles

C - 74.1 g - 74.1 g/12 g/mol = 6.17 mol

H - 8.6 g - 8.6 g / 1 g/mol = 8.6 mol

N - 17.3 g - 17.3 g / 14 g/mol = 1.23

divide all by the least number of moles

C - 6.17 / 1.23 = 5.01

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we have to find what the mass of 1 empirical unit is

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3 years ago
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Please leave workings as well
yulyashka [42]

Answer:

15g

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