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zaharov [31]
3 years ago
14

How many moles of NaCI are in 250.0 ml of a 0.35 M NaCl solution?

Chemistry
1 answer:
AnnZ [28]3 years ago
6 0

<u>Answer:</u> The number of moles of NaCl in the solution are 0.0875 moles.

<u>Explanation:</u>

To calculate the number of moles of NaCl, we use the equation that is used to calculate molarity, which is:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

We are given:

Molarity of NaCl solution = 0.35 mol/L

Volume of solution = 250 mL = 0.250 L      (Conversion factor:  1L = 1000 mL)

Putting values in above equation, we get:

0.35mol/L=\frac{\text{Moles of NaCl}}{0.250L}\\\\\text{Moles of NaCl}=0.0875mol

Hence, the number of moles of NaCl in the solution are 0.0875 moles.

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True or false: covalent compounds are formed when two nonmetals share valance electrons
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Answer:

true

Explanation:

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Answer:

1. The product has a higher Rf value on a silica gel TLC plate because it is more polar than the starting methyl benzoate.

2. False

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In comparing the electrophillic aromatic substitution of m-nitrobenzoate  and methyl benzoate, we must remember that the presence of electron withdrawing groups (such as -NO2 and -CHO) on the aromatic compound deactivates the compound towards electrophillic aromatic substitution hence, methyl m-nitrobenzoate is less reactive than methyl benzoate in Electrophilic Aromatic Substition and Methyl benzoate is less reactive than benzene in Electrophilic Aromatic Substition

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p3=0.36atm (partial pressure of NOCl)

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