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zaharov [31]
3 years ago
14

How many moles of NaCI are in 250.0 ml of a 0.35 M NaCl solution?

Chemistry
1 answer:
AnnZ [28]3 years ago
6 0

<u>Answer:</u> The number of moles of NaCl in the solution are 0.0875 moles.

<u>Explanation:</u>

To calculate the number of moles of NaCl, we use the equation that is used to calculate molarity, which is:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

We are given:

Molarity of NaCl solution = 0.35 mol/L

Volume of solution = 250 mL = 0.250 L      (Conversion factor:  1L = 1000 mL)

Putting values in above equation, we get:

0.35mol/L=\frac{\text{Moles of NaCl}}{0.250L}\\\\\text{Moles of NaCl}=0.0875mol

Hence, the number of moles of NaCl in the solution are 0.0875 moles.

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Determine the percent composition by mass of a 100g salt solution which contains 20g salt
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Answer:

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so; mass of solute=80g

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=  \frac{20}{100}  \times 100 \\  = 20\%

glad to help you

hope it helps

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