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zaharov [31]
4 years ago
14

How many moles of NaCI are in 250.0 ml of a 0.35 M NaCl solution?

Chemistry
1 answer:
AnnZ [28]4 years ago
6 0

<u>Answer:</u> The number of moles of NaCl in the solution are 0.0875 moles.

<u>Explanation:</u>

To calculate the number of moles of NaCl, we use the equation that is used to calculate molarity, which is:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

We are given:

Molarity of NaCl solution = 0.35 mol/L

Volume of solution = 250 mL = 0.250 L      (Conversion factor:  1L = 1000 mL)

Putting values in above equation, we get:

0.35mol/L=\frac{\text{Moles of NaCl}}{0.250L}\\\\\text{Moles of NaCl}=0.0875mol

Hence, the number of moles of NaCl in the solution are 0.0875 moles.

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Calculate the grams of ethane present in a sample containing 0.4271 moles if the molar mass of ethane is 30.067 g/mol.
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The grams of ethane present in a sample containing 0.4271 mole is 12.84 g

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation

Mole = mass / molar mass

With the above formula, we can obtain the mass of ethane. Details below

<h3>How to determine the mass of ethane</h3>

The following data were obtained from the question:

  • Mole of ethane = 0.4271 mole
  • Molar mass of ethane = 30.067 g/mol
  • Mass of ethane =?

The mass of ethane present in the sample can be obtained as follow:

Mole = mass / molar mass

Cross multiply

Mass = mole × molar mass

Mass of ethane = 0.4271 × 30.067

Mass of ethane = 12.84 g

Learn more about mole:

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