The given chemical reaction is:
Δ
∑BE(reactants)-∑BE(products)
= {(941 kJ/mol) + (3 * 242 kJ/mol)} -[{2*(3*200 kJ/mol)}]
= 467 kJ/mol
Calculating the change in heat when 85.3 g chlorine reacts in the above reaction:
Moles of chlorine = 
= 1.20 mol 
Heat change when 1.20 mol chlorine reacts
= 
The answer to this item is determined by using the proper conversion factors and the dimensional analysis. For the given units, meter and centimeters, the conversion from millimeters are as shown below,
1 m = 1000 mm
1 cm = 10 mm
Conversion of 5.3 mm³ to m³.
= (5.3 mm³)(1 m/1000 mm)³ = 5.3 x 10⁻⁹ m³
Conversion of 5.3 mm³ to cm³.
= (5.3 mm³)(1 cm/10 mm)³ = 5.3 x 10⁻³ cm³
The answer to this item is therefore letter B. 5.3 x 10⁻⁹ m³.
Answer:
the temperature of the system decreases
The answer is no.(4) They frequently have long half-lives and remain radioactive for extended periods of time
For example, half life of Uranium (U) varies from 25 thousand years to 4.5 billion years
Answer:
109.34 g
Explanation:
2NaOH(aq) + H2SO4(aq) ------> Na2SO4(aq) + 2H2O(l)
Number of moles of NaOH = 105g/40g/mol = 2.6 moles
From the reaction equation;
2 moles of NaOH yields 1 mole of sodium sulphate
2.6 moles of NaOH yields = 2.6 × 1/2 = 1.3 moles of sodium sulphate
Number of moles of H2SO4= 75.5g/98 g/mol = 0.77 moles
From the reaction equation;
1 mole of H2SO4 yields 1 mole of sodium sulphate
Hence, 0.77 moles of H2SO4 yields 0.77 moles of sodium sulphate
So H2SO4 is the limiting reactant.
Theoretical yield = number of moles × molar mass
= 0.77 mol ×142 g/mol
= 109.34 g
