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larisa86 [58]
4 years ago
11

En que parte de la isla de cuba tuvieron lugar los principales acontecimientos de la guerra de independencia?

Physics
1 answer:
DedPeter [7]4 years ago
8 0

Answer:

El 24 de febrero de 1895, por órdenes de Martí se levantan 35 aldeas en el Oriente de Cuba en lo que se ha dado en llamar el Grito de Baire.

Entre los lugares están Ibarra, Guantánamo y Manzanillo.

Explanation:

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Gravitational forces is ------ force​
mel-nik [20]

Answer:

Gravitational force is <u>noncontact</u> force

Explanation:

Contact force occurs due to the contact between two different objects. Non-contact force occurs due to either attraction or repulsion between two objects such that there is no contact between these objects. There is no field linked with the contact force. ... Gravitational force is an example of a non-contact force.

7 0
3 years ago
To overcome the problems that blur images and don't provide the best resolution from Earth, astronomers have started using flexi
schepotkina [342]

Answer:

adaptive optics

Explanation:

simple

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3 years ago
Kepler's second law, which states that as a planet moves around its orbit it sweeps out equal areas in equal times, means that K
erastovalidia [21]

Explanation:

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3 0
3 years ago
A student performs this experiment and measures the bar to have a mass of 150g and length of 36cm. What is the moment of inertia
Ugo [173]

Answer:

The moment of inertia of the bar is 45\times10^{-4}\ kg-m^2

Explanation:

Given that,

mass of bar = 150 g

Length l = 36 cm

We need to calculate the moment of inertia of the bar

Using formula of moment inertia

I=\dfrac{1}{12}Ml^2

Where,

M = mass of the bar

L = length of the bar

Put the value into the formula

I=\dfrac{1}{12}\times150\times10^-3\times36\times10^{-2}

I=45\times10^{-4}\ kg-m^2

Hence, The moment of inertia of the bar is 45\times10^{-4}\ kg-m^2

4 0
4 years ago
A 10.1 g bullet leaves the muzzle of a rifle with a speed of 425 m/s. What constant force is exerted on the bullet while it is t
PIT_PIT [208]

Answer

Force will be 1520.2604 N

Explanation:

We have given mass of the bullet m = 10.1 gram = 0.0101 kg

Distance S= 0.6 m

Final velocity v = 425 m/sec

Initial velocity u will be 0 m/sec

From third equation of motion v^2=u^2+2as

425^2=0^2+2\times a\times 0.6

a=150520.833m/sec^2

We know that force is given by F = ma

So force = 0.0101×150520.833 = 1520.2604 N

5 0
3 years ago
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