Force of earth gravity on 1 kg mass is 9.8 N.
Since the mass is at earth surface, therefore its distance from the centre of earth is equal to the radius of the earth i.e. 6400 km.
The force of earth gravity is calculated as
F=GMm/r^2 =(6.67*〖10〗^(-11)*6*〖10〗^24*1)/〖(64*〖10〗^6)〗^2 =9.8 N
Answer:
Ok, the minimal quantity of charge that we can find is on the electron or in the proton (the magnitude is the same, but the sign is different)
Where the charge of a single proton is:
C = 1.6x10^-19 C
Now, you need to remember that when we are working with charges, we are working with discrete math:
What means that?
If the minimum positive is the charge of one proton, then the consecutive charge will be the charge of two protons (there is no somethin in between)
So the consecutive charge will be:
C = 2*1.6x10^-19 C = 3.2x10^-19 C.
So, because we are working in discrete math, we can not have any object that has charge between 1.6x10^-19 C and 3.2x10^-19 C.
Particularly, 2.0x10^-19 C is in that range, so we can conclude that:
No, an object can not carry a charge of 2.0x10^-19 C.
In an atom, you have three particles: protons, electrons, and neutrons.
When you add or subtract electrons from an atom, it means that there are either more protons than electrons (positively charged) or there are more electrons than protons (negatively charged).
You cannot add or subtract protons since they are the atomic number, which means the number of protons determines the element. Neutrons have a neutral charge, so they wouldn't affect the charge at all.
By tightening a string you are actually putting more stress on the string you are giving it a new frequency that isn't natural.
Hope this helps
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Answer:
The answer is chemical energy, so that would be D
Explanation: