How do you solve for net force

A series circuit connects a single light bulb to a single power source. As more light bulbs are added to the circuit, which grap

Nikolay [14]

Answer: B

Explanation:

3 0

3 years ago

Two long, straight wires are separated by 0.120 m. The wires carry currents of 11 A in opposite directions, as the drawing indic

rewona [7]

Answer:

The magnitude of the magnetic field is 1.83 x $10^{-5}$ T.

Explanation:

The flow of an electric current in a straight wire induces magnetic field around the wire. When current is flowing through two wires in the same direction, a force of attraction exists between the wires. But if the current flows in opposite directions, the force of repulsion is felt by the wires.

In the given question, the direction of flow of current through the wires is opposite, thus both wires applies the same field on each other. The result to repulsion between them.

The magnetic field (B) between the given wires can be determined by:

B = $\frac{U_{o}I }{2\pi r}$

where: I is the current, r is the distance between the wires and $U_{0}$ is the magnetic field constant.

But, I = 11 A, r = 0.12 m and $U_{0}$ = 4 $\pi$ x $10^{-7}$ Tm/A

So that;

B = $\frac{4\pi *10^{-7}*11 }{2\pi *0.12}$

= 1.8333 x $10^{-5}$

B = 1.83 x $10^{-5}$ T

6 0

3 years ago

If the current flowing through an electric heater increases from 6 to 12 amp while the voltage remains the same, the heat produc

Ainat [17]

Q=l^2 times R times t
Where Q - heat, I -current, R - resistance and t is time

If you increase I twice (and it's squared), than Q gonna went up 4 times (2 squared).

Choose last

8 0

4 years ago

Read 2 more answers

An AC adapter for a telephone-answering unit uses a transformer to reduce the line voltage of 120 V (rms) to a voltage of 9.0 V.

Illusion [34]

Answer:

1. The number of turns on the secondary output is 18

2. The root mean square power delivered to the transformer is 48 Watts.

Explanation:

A transformer is an electronic device that can be used for increasing or decreasing the value of a given voltage. It consists of primary coils and secondary coil of a definte number of turns. When voltage flows in the primary coil, it induces voltage in the secondary coil. The two types are: step-up and step down transformers.

1. For a given transformer,

$\frac{V_{s} }{V_{p} }$ = $\frac{N_{s} }{N_{p} }$

where $V_{s}$ is the value of the induced voltage in the secondary coil, $V_{p}$ is he voltage in the primary coil, and $N_{s}$ is the number of turns of the secondary coil, $N_{p}$ is the number of turns in the primary coil.

From the question,

$V_{s}$ = 9.0 V, $V_{p}$ = 120 V, $N_{p}$ = 240, $N_{s}$ = ?

So that,

$N_{s}$ = $\frac{V_{s}*N_{p} }{V_{p} }$

= $\frac{9 * 240}{120}$

= 18

The number of turns on the secondary output is 18.

2. $Power_{rms}$ = $I_{rms}$ × $V_{rms}$

= 0.4 × 120

= 48 W

The rms power delivered to the transformer is 48 Watts.

8 0

3 years ago

distant galaxy emits light that has a wavelength of 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm.

a_sh-v [17]

Answer:

The speed of the galaxy relative to the Earth is $3.09\times 10^6\ m/s$ .

Explanation:

We have,

(a) Wavelength emitted by light at distant galaxy is 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm. It can be seen that the wavelength of light reduces as it reaches Earth. It is called Red shift. As per Doppler's effect, we can say that the galaxy is receding from the Earth.

(b) Let v is the speed of the galaxy relative to the Earth. It can be given by :

$v=c(\dfrac{\lambda'}{\lambda}-1)\\\\v=3\times 10^8\times (\dfrac{438.6 }{434.1 }-1)\\\\v=3\times 10^8\times (\dfrac{438.6}{434.1}-1)\\\\v=0.0103\cdot3\cdot10^{8}\\\\v=3.09\times 10^6\ m/s$

So, the speed of the galaxy relative to the Earth is $3.09\times 10^6\ m/s$ .

4 0

3 years ago