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Sati [7]
4 years ago
10

How do you solve for net force

Physics
1 answer:
steposvetlana [31]4 years ago
5 0

Answer:

according to my calculator

Explanation:

4x+5g=9t

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Critical Thinking
Sophie [7]
OK.

You're sitting in a soft comfy chair, reading a book in your lap.
The book stays put, and you eventually start to get sleepy, because
there's almost no acceleration happening.

The chair you're sitting in is seat #27B in a huge jet taking you to visit
your grandparents who live a thousand miles away.
The airplane is maybe 7 miles up, passing over the ground at nearly
500 miles per hour, flying straight, level, and fast !
6 0
3 years ago
The label on a bottle of soda can shows the can contains 397 ml of soda how many litters of soda are in one can
Basile [38]

Answer:

A

Explanation:

1000ml = 1l

397ml = 0.397l

8 0
3 years ago
If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation w
Elina [12.6K]
The answer is letter C.

Weight (on Earth) is the force due to the mass of Earth attracting whatever mass is subject of discussion.

The force of attraction between any two masses is called Newton's Law of Universal Gravitation:

G \frac{m_1m_2}{d^2}

G is simply a given constant.

If we're at the surface of Eath, m_1 refers to the mass of the Earth, m_2 to the mass of whatever is on the surface of Earth, and d to the radius of Earth. 

Normally, we define a constant g to be equal to G \frac{M}{r^2}; in which M is the mass of Earth and r the radius of earth; g happens to be around 9.8.

By that, we adapt the Law of Universal Gravitation to objects on the surface of Earth, we call that force Weight.

W=mg

As you can see, weight is directly proportional to mass, more mass implies more weight.
8 0
4 years ago
Which of the following characteristics of Earth's crust is likely to contribute to geological events?
olganol [36]

Answer:A

Explanation:

The crust Of The earth's has plates boundaries,when the layers that forms to boundaries glide on each other, vibrations occur which are known as earthquakes

8 0
3 years ago
A 1250-kg compact car is moving with velocity v1 =36.2i^+12.7j^m/s. It skids on a frictionless icy patch and collides with a 448
MA_775_DIABLO [31]

Momentum is conserved, so the sum of the separate momenta of the car and wagon is equal to the momentum of the combined system:

(1250 kg) ((36.2 <em>i</em> + 12.7 <em>j </em>) m/s) + (448 kg) ((13.8 <em>i</em> + 10.2 <em>j</em> ) m/s) = ((1250 + 448) kg) <em>v</em>

where <em>v</em> is the velocity of the system. Solve for <em>v</em> :

<em>v</em> = ((1250 kg) ((36.2 <em>i</em> + 12.7 <em>j </em>) m/s) + (448 kg) ((13.8 <em>i</em> + 10.2 <em>j</em> ) m/s)) / (1698 kg)

<em>v</em> ≈ (30.3 <em>i</em> + 12.0 <em>j</em> ) m/s

7 0
3 years ago
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