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Sati [7]
3 years ago
10

How do you solve for net force

Physics
1 answer:
steposvetlana [31]3 years ago
5 0

Answer:

according to my calculator

Explanation:

4x+5g=9t

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Which portion of the electromagnetic spectrum is used to identify fluorescent minerals?
S_A_V [24]
<h2>Answer: Ultraviolet Light </h2>

Ultraviolet light, whose wavelength is approximately between 100 nm and 380 nm; is a type of electromagnetic radiation that is not visible to the human eye.

This light is used for many purposes, among which is the identification of fluerescent minerals.

In this sense, fluorescence is a property that certain materials have in which they absorb energy in the form of short wavelength not visible electromagnetic radiation (the ultraviolet, for example) and then emit some of that energy in the form of longer wavelength electromagnetic radiation (in the visible spectrum). This is also called luminiscence.

Hence, the correct option is a.

6 0
3 years ago
Tornadoes are most frequent from _____. April to June October to December January to March July to August
jenyasd209 [6]

Answer:

April to June

Explanation:

Not really an explanation, I just know it.

8 0
3 years ago
A wave traveling in water has a frequency of 250 Hz and a wavelength of 6.0 m. What is the speed of the wave
Aleks04 [339]
Speed of wave = frequency x wavelength
                        =     250 x 6 = 1500 m/s.
7 0
3 years ago
"A uniform cylinder of mass M and radius R is rolling without slipping. The velocity of its center of mass is v. What is the cyl
Goshia [24]

Answer:

Explanation:

Given

mass of cylinder is M

radius R

velocity of center of mass is v

As there is no slipping therefore cylinder will rotate as well as translate

Moment of inertia of cylinder I=\frac{MR^2}{2}

Kinetic Energy of cylinder K.E.=\frac{1}{2}Mv^2

Rotational energy R.E.=\frac{1}{2}I\omega ^2

for rolling

v=\omega \times r

where \omega =angular\ velocity\ of\ cylinder

R.E.=\frac{1}{2}\times \frac{MR^2}{2}\times (\frac{v}{R})^2=\frac{1}{4}Mv^2

Total kinetic Energy =\frac{1}{2}Mv^2+\frac{1}{4}Mv^2=\frac{3}{4}Mv^2

6 0
3 years ago
(PLS HELP 20 POINTS, IM TOO DUMB FOR THIS) What is the total momentum of the system after the collision?​
Dmitry_Shevchenko [17]
Using the law of conservation of momentum
m1u1+m2u2=m1v1+m2v2
Where m1 is mass of first object
m2 is mass of second object
u1 and u2 are initial velocities of object 1 and 2 respectively
v1 and v2 are final velocities of object 1 and 2 respectively
Here, they are moving as a system after collision. Thus they will posses same final velocity
m1u1 +m2u2=v(m1+m2)
Substituting values
600*4+0=v(600+400)
2400=v*1000
v=2.4 m/s

Now momentum of system
p=Mv
p=(600+400)*2.4
p=1000*2.4
Therefore p=2400 kg m/s
Hope this helps :)
6 0
4 years ago
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