Answer:
25N.s=25kgm/s
Explanation:
The resulting momentum in this case is equal to the impulse created by the force 5N during 5 seconds
ΔP=Force.time=F.t
= 5x5=25kgm/s
Electromagnetic waves are waves consists of waves of the electromagnetic field, propagating through the space, carrying electromagnetic radiant energy. Examples includes radio waves, microwaves, infrared, light, ultraviolet, X-rays, and gamma rays. All of these waves form part of the electromagnetic spectrum.
In order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.
Learn more about electromagnetic waves:
brainly.com/question/14015797
Mechanical advantage<span> <span>is a measure of the force amplification
achieved by using a tool, </span>mechanicaldevice or
machine system. Ideally, the
device preserves the input power and simply trades off forces against movement
to obtain a desired amplification in the output force. The model for this is
the law of the lever. So the ima is 3/1.5 = 2</span>
Answer:
<em>a) Jack does more work uphill</em>
<em>b) Numerically, we can see that Jill applied the most power downhill</em>
<em></em>
Explanation:
Jack's mass = 75 kg
Jill's mass = 
Jill's mass = 
= 50 kg
distance up hill = 15 m
a) work done by Jack uphill = mgh
where g = acceleration due to gravity= 9.81 m/s^2
work = 75 x 9.81 x 15 = <em>11036.25 J</em>
similarly,
Jill's work uphill = 50 x 9.81 x 15 = <em>7357.5 J</em>
<em>this shows that Jack does more work climbing up the hill</em>
<em></em>
b) assuming Jack's time downhill to be t,
then Jill's time = 
we recall that power is the rate in which work id done, i.e
P = 
For Jack, power = 
For Jill, power = 
= 
<em>Numerically, we can see that Jill applied the most power downhill</em>
Answer:
Option 3 = both spheres are at the same potential.
Explanation:
So, let us complete or fill the missing gap in the question above;
" A charge is placed on a spherical conductor of radius r1. This sphere is then connected to a distant sphere of radius r2 (not equal to r1) by a conducting wire. After the charges on the spheres are in equilibrium BOTH SPHERES ARE AT THE SAME POTENTIAL"
The reason both spheres are at the same potential after the charges on the spheres are in equilibrium is given below:
=> So, if we take a look at the Question again, the kind of connection described in the question above (that is a charged sphere, say X is connected another charged sphere, say Y by a conducting wire) will eventually cause the movement of charges(which initially are not of the same potential) from X to Y and from Y to X and this will continue until both spheres are at the same potential.
