1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shtirlitz [24]
3 years ago
5

The Reynolds number, rhoVD/μ is a very important parameter in fluid mechanics. Determine its value for ethyl alcohol flowing at

a velocity of 4 m/s through a 2-in.-diameter pipe.
Engineering
1 answer:
ElenaW [278]3 years ago
8 0

Answer:

The Reynold Number is 146415.34

Explanation:

The density of ethyl alcohol = ρ = 789 kg/m^3

The dynamic viscosity of ethyl alcohol = μ = 0.001095 kg/m.s

Velocity = V = 4 m/s

Diameter of pipe = D = 2 in = 0.0508 m

The Reynold's number (Re), will be:

Re = ρVD/μ

Re = (789 kg/m^3)(4 m/s)(0.0508 m)/(0.001095 kg/ms)

<u>Re = 146415.34</u>

You might be interested in
You have a 12 volt power source running through a circuit that has 3kΩ of resistance, how many amps (in mA) can flow through the
siniylev [52]

Answer:

4mA

Explanation:

For this problem, we will simply apply Ohm's law:

V = IR

V/R = I

I = V / R

I = 12 volt / 3kΩ

I = 4mA

Hence, the current in the circuit is 4mA.

Cheers.

5 0
2 years ago
A light pressure vessel is made of 2024-T3 aluminum alloy tubing with suitable end closures. This cylinder has a 90mm OD, a 1.65
Andru [333]

Given:

Outer Diameter, OD = 90 mm

thickness, t = 0.1656 mm

Poisson's ratio, \mu = 0.334

Strength = 320 MPa

Pressure, P =3.5 MPa

Formula Used:

1).  Axial Stress_{max} = P[\frac{r_{o}^{2} + r_{i}^{2}}{r_{o}^{2} - r_{i}^{2}}]

2). factor of safety, m = \frac{strength}{stress_{max}}

Explanation:

Now, for Inner Diameter of cylinder, ID = OD - 2t

ID = 90 - 2(1.65) = 86.7 mm

Outer radius,  r_{o} = 45mm

Inner radius,  r_{i} = 43.35 mm

Now by using the given formula (1)

  Axial Stress_{max} = 3.5[\frac{45^{2} + 43.35^{2}}{45^{2} - 43.35^{2}}]

  Axial Stress_{max} = 3.5\times 26.78 =93.74 MPa

Now, Using formula (2)

factor of safety, m = \frac{320}{93.74} = 3.414

7 0
3 years ago
An aluminium alloy bar of diameter 12.5 mm and length 27 m loaded in uniaxial tension to a force of 3 kN. Determine the length o
KonstantinChe [14]

Answer:

27009.56 mm

Explanation:

Given:

Diameter of the aluminium alloy bar, d = 12.5 mm

Length of the bar, L = 27 m = 27 × 10³ mm

Tensile force, P = 3 KN = 3 × 10³ N

Elastic modulus of the bar, E = 69 GPa = 69 × 10³ N/mm²

Now,

for the uniaxial loading, the elongation or the change in length (δ) due to the applied load is given as:

\delta=\frac{PL}{AE}

where, A is the area of the cross-section

A=\frac{\pi d^2}{4}

or

A=\frac{\pi\times12.5^2}{4}

or

A = 122.718 mm²

on substituting the respective values in the formula, we get

\delta=\frac{3\times10^3\times27\times10^3}{122.718\times69\times10^3}

or

δ = 9.56 mm

Hence, the length after the force is applied = L + δ = 27000 + 9.56

= 27009.56 mm

7 0
3 years ago
Write a Nested While Loop that will increment the '*' from 1 to 10.
andrey2020 [161]

Answer:

The program is as follows:

i = 1

while(i<11):

   j = 1

   while(j<=i):

       print('*', end = '')

       j += 1

   i += 1

   print()

Explanation:

Initialize i to 1

i = 1

The outer loop is repeated as long as i is less than 11

while(i<11):

Initialize j to 1

   j = 1

The inner loop is repeated as long as j is less than or equal i

   while(j<=i):

This prints a *

       print('*', end = '')

This increments j and ends the inner loop

       j += 1

This increments i

   i += 1

This prints a blank and ends the inner loop

   print()

8 0
3 years ago
Fatigue failure occurs under the condition of (a) High elastic stress (b) High corrosivity (c) High stress fluctuations (d) High
Harlamova29_29 [7]

Answer:

Fatigue occurs under conditions of high elastic stress, high stress fluctuations and high rate of loading

Explanation:

 According to many definition of fatigue failure the fatigue occurs when in an especifyc point of the object there is involved many forces and tensions.

 That tensions needs to be big in magnitud, de variations of the efforts it has to be with a lot of amplitude and the loading in the object it has to be with a lot of number of cycles.

 If in the all of these three conditions are present the fatigue failure it would appear.

8 0
3 years ago
Other questions:
  • Two points along a wire are labeled Xand Y. The current is measured to be iXY= –3A.The reference direction of iXY is defined by
    11·1 answer
  • At the end of a power distribution system, a certain feeder supplies three distribution transformer, each one supplying a group
    8·1 answer
  • A wall in a house contains a single window. The window consists of a single pane of glass whose area is 0.15 m2 and whose thickn
    10·1 answer
  • Consider the gas carburizing of a gear of 1018 steel (0.18 wt %) at 927°C (1700°F). Calculate the time necessary to increase the
    12·1 answer
  • Using the data from the table, what is P(3)?!
    9·1 answer
  • What is meant by the thickness to chord ratio of an aerofoil?
    12·1 answer
  • An automobile engine consumes fuel at a rate of 22 L/h and delivers 85 kW of power to the wheels. If the fuel has a heating valu
    8·2 answers
  • Parting tool purpose
    13·1 answer
  • Entor" by
    9·1 answer
  • Describe the meaning of the different symbols and abbreviations found on the documents that they use
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!