Answer:
4mA
Explanation:
For this problem, we will simply apply Ohm's law:
V = IR
V/R = I
I = V / R
I = 12 volt / 3kΩ
I = 4mA
Hence, the current in the circuit is 4mA.
Cheers.
Given:
Outer Diameter, OD = 90 mm
thickness, t = 0.1656 mm
Poisson's ratio,
= 0.334
Strength = 320 MPa
Pressure, P =3.5 MPa
Formula Used:
1).
=
2). factor of safety, m = 
Explanation:
Now, for Inner Diameter of cylinder, ID = OD - 2t
ID = 90 - 2(1.65) = 86.7 mm
Outer radius,
= 45mm
Inner radius,
= 43.35 mm
Now by using the given formula (1)
=
=
=93.74 MPa
Now, Using formula (2)
factor of safety, m = \frac{320}{93.74} = 3.414
Answer:
27009.56 mm
Explanation:
Given:
Diameter of the aluminium alloy bar, d = 12.5 mm
Length of the bar, L = 27 m = 27 × 10³ mm
Tensile force, P = 3 KN = 3 × 10³ N
Elastic modulus of the bar, E = 69 GPa = 69 × 10³ N/mm²
Now,
for the uniaxial loading, the elongation or the change in length (δ) due to the applied load is given as:

where, A is the area of the cross-section

or

or
A = 122.718 mm²
on substituting the respective values in the formula, we get

or
δ = 9.56 mm
Hence, the length after the force is applied = L + δ = 27000 + 9.56
= 27009.56 mm
Answer:
The program is as follows:
i = 1
while(i<11):
j = 1
while(j<=i):
print('*', end = '')
j += 1
i += 1
print()
Explanation:
Initialize i to 1
i = 1
The outer loop is repeated as long as i is less than 11
while(i<11):
Initialize j to 1
j = 1
The inner loop is repeated as long as j is less than or equal i
while(j<=i):
This prints a *
print('*', end = '')
This increments j and ends the inner loop
j += 1
This increments i
i += 1
This prints a blank and ends the inner loop
print()
Answer:
Fatigue occurs under conditions of high elastic stress, high stress fluctuations and high rate of loading
Explanation:
According to many definition of fatigue failure the fatigue occurs when in an especifyc point of the object there is involved many forces and tensions.
That tensions needs to be big in magnitud, de variations of the efforts it has to be with a lot of amplitude and the loading in the object it has to be with a lot of number of cycles.
If in the all of these three conditions are present the fatigue failure it would appear.