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Elenna [48]
2 years ago
7

Javier’s class visited a power plant near his city, and they learned how it produced electricity. What does this form of power d

epend on for generating electricity?
Engineering
1 answer:
adelina 88 [10]2 years ago
5 0

The electricity is generated by the burning of fuel in the power plant that increases the kinetic energy of water vapor which rotates the turbine and shaft of the generator.

<h3>What is a power plant?</h3>

A power plant is a place where heavy machinery objects are installed to produce electricity.

The power is generated in the power plant with the help of the burning of fuel that increases the temperature of the boiler. There are so many tubes in which water is present. Water absorbs heat and increases its kinetic energy. And this kinetic energy help to rotate the turbine and the shaft of the generator is attached to the turbine as result electricity is generated.

More about the power plant link is given below.

brainly.com/question/7670779

#SPJ4

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2 years ago
A tank with some water in it begins to drain. The function v ( t ) = 46 − 3.5 t determines the volume of the water in the tank (
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Answer with Explanation:

Part a)

The volume of water in the tank as a function of time is plotted in the below attached figure.

The vertical intercept of the graph is 46.

Part b)

The vertical intercept represents the volume of water that is initially present in the tank before draining begins.

Part c)

To find the time required to completely drain the tank we calculate the volume of the water in the tank to zero.

0=46-3.5t\\\\3.5=46\\\\\therefore t=\frac{46}{3.5}=13.143minutes

Part d)

The horizontal intercept represents the time it takes to empty the tank which as calculated above is 13.143 minutes.

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3 years ago
Determine the required dimensions of a column with a square cross section to carry an axial compressive load of 6500 lb if its l
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Answer: 0.95 inches

Explanation:

A direct load on a column is considered or referred to as an axial compressive load. A direct concentric load is considered axial. If the load is off center it is termed eccentric and is no longer axially applied.

The length= 64 inches

Ends are fixed Le= 64/2 = 32 inches

Factor Of Safety (FOS) = 3. 0

E= 10.6× 10^6 ps

σy= 4000ps

The square cross-section= ia^4/12

PE= π^2EI/Le^2

6500= 3.142^2 × 10^6 × a^4/12×32^2

a^4= 0.81 => a=0.81 inches => a=0.95 inches

Given σy= 4000ps

σallowable= σy/3= 40000/3= 13333. 33psi

Load acting= 6500

Area= a^2= 0.95 ×0.95= 0.9025

σactual=6500/0.9025

σ actual < σallowable

The dimension a= 0.95 inches

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