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Mila [183]
2 years ago
12

Maple has a sample of graphite, which is made up of carbon atoms. She has 1.810 x 1024 atoms of carbon. What is the mass of this

sample?
Chemistry
2 answers:
Lera25 [3.4K]2 years ago
4 0

Answer:

  about 36.10 g

Explanation:

The proportion of interest is ...

  mass/atoms = x/(1.810·10^24) = (12.0107 g)/(6.02214076·10^23)

Multiplying by 1.810·10^24, we find the mass of the sample to be ...

  x = 36.0991 g

The mass of the sample is about 36.10 grams (to 4 s.f.).

zysi [14]2 years ago
3 0

Answer:

<h2> <u>about</u><u> </u><u>3</u><u>6</u><u>.</u><u>1</u><u>0</u><u> </u><u>g</u></h2>

  • <em>the</em><em> </em><em>mass</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>given</em><em> </em><em>maple</em><em> </em><em>which</em><em> </em><em>she</em><em> </em><em>has</em><em> </em><em>1</em><em>.</em><em>8</em><em>1</em><em>0</em><em>×</em><em>1</em><em>0</em><em>2</em><em>5</em><em> </em><em>atoms</em><em> </em><em>of</em><em> </em><em>carbon</em><em> </em><em>is</em><em> </em><em>equal</em><em> </em><em>of</em><em> </em><em><u>about</u></em><em><u> </u></em><em><u>3</u></em><em><u>6</u></em><em><u>.</u></em><em><u>1</u></em><em><u>0</u></em><em><u> </u></em><em><u>G</u></em><em><u>/</u></em><em><u>grams</u></em><em><u>.</u></em>
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Iron fluoride (FeF2) dissociates according to the following equation:
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Answer:

S = 0.788 g/L

Explanation:

The solubility product (Kps) is an equilibrium solubization constant, which can be calculated by the equation:

Kps = \frac{[product]^x}{[reagent]^y}

Where x and y are the stoichiometric coefficients of the product and the reagent, respectively. Because of the aggregation form, the concentration of solids is always equal to 1 for use in this equation.

Analyzing the equation, we see that for 1 mol of Fe^{+2} is necessary 2 mols of F^-, so if we call "x" the molar concentration of Fe^2, for F^- we will have 2x, so:

Kps = [Fe^{+2}].[F^-]^2\\\\2.36x10^{-6} = x(2x)^2\\\\2.36x10^{-6} = 4x^3\\\\x^3 = 5.9x10^{-7}\\\\x = \sqrt[3]{5.9x10^{-7}} \\\\x = 8.4x10^{-3} mol/L

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So,

[tex]S = 8.4x10^{-3}x93.8

S = 0.788 g/L

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