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3 years ago

Pls help me its due in 20 minutes.

Chemistry

2 answers:

scZoUnD [109]3 years ago

8 0

Answer:

11. 1, 4.5

12. right; 4.5 > 1

13. 10, 3

14. left; 10 > 3

Explanation:

Sveta_85 [38]3 years ago

4 0

Answer:

11. 1, 4.5

12. right; 4.5 > 1

13. 10, 3

14. left; 10 > 3

Explanation:

All you're being asked to do is count the squares in the pictures.

11. The number of squares for the left wave from bottom to top is 2, so the amplitude is 1/2 that, 2/2 = 1. For the right wave it is 9 squares from bottom to top, so the amplitude is 9/2 = 4.5.

left amplitude: 1, right amplitude: 4.5

12. The right wave has greater amplitude. Evidence: 4.5 > 1. It also takes up more vertical space in the picture.

13. It is difficult to determine the wavelength of the left wave, because two full peaks are not shown. If we try to match corresponding points, they appear to be about 10 squares apart.

The right wave has 2 peaks in 6 squares, so about 3 squares between peaks.

left: wavelength 10, right: wavelength 3

14. The left wave has greater wavelength. Evidence: 10 > 3.

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For the following reaction, KcKc = 255 at 1000 KK.

bonufazy [111]

Answer :

The equilibrium concentration of CO is, 0.016 M

The equilibrium concentration of Cl₂ is, 0.034 M

The equilibrium concentration of COCl₂ is, 0.139 M

Explanation :

The given chemical reaction is:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial conc. 0.1550 0.173 0

At eqm. (0.1550-x) (0.173-x) x

As we are given:

$K_c=255$

The expression for equilibrium constant is:

$K_c=\frac{[COCl_2]}{[CO][Cl_2]}$

Now put all the given values in this expression, we get:

$255=\frac{(x)}{(0.1550-x)\times (0.173-x)}$

x = 0.139 and x = 0.193

We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.139

The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M

The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M

The equilibrium concentration of COCl₂ = x = 0.139 M

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Answer:

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