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Oksi-84 [34.3K]
3 years ago
14

Pls help me its due in 20 minutes.

Chemistry
2 answers:
scZoUnD [109]3 years ago
8 0

Answer:

11. 1, 4.5

12. right; 4.5 > 1

13. 10, 3

14. left; 10 > 3

Explanation:

Sveta_85 [38]3 years ago
4 0

Answer:

  11. 1, 4.5

  12. right; 4.5 > 1

  13. 10, 3

  14. left; 10 > 3

Explanation:

All you're being asked to do is count the squares in the pictures.

11. The number of squares for the left wave from bottom to top is 2, so the amplitude is 1/2 that, 2/2 = 1. For the right wave it is 9 squares from bottom to top, so the amplitude is 9/2 = 4.5.

  left amplitude: 1, right amplitude: 4.5

__

12. The right wave has greater amplitude. Evidence: 4.5 > 1. It also takes up more vertical space in the picture.

__

13. It is difficult to determine the wavelength of the left wave, because two full peaks are not shown. If we try to match corresponding points, they appear to be about 10 squares apart.

The right wave has 2 peaks in 6 squares, so about 3 squares between peaks.

  left: wavelength 10, right: wavelength 3

__

14. The left wave has greater wavelength. Evidence: 10 > 3.

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Please help on how to solve this problem it’s for isotopes
wlad13 [49]

Mg-19:

#protons = 12

#neutrons = 7

#electrons = 12

Mg-40:

#protons = 12

#neutrons = 28

#electrons = 12

8 0
3 years ago
The decomposition of copper(II) nitrate on heating is endothermic reaction. 2Cu(NO3)2(s) → 2C10(s) + 4NO2(g) + O2(g) Calculate t
Basile [38]

Answer:

The enthalpy change for the given reaction is 424 kJ.

Explanation:

2Cu(NO_3)_2(s)\rightarrow 2CuO(s) + 4NO_2(g) + O_2(g),\Delta H_{rxn}=?

We have :

Enthalpy changes of formation of following s:

\Delta H_{f,Cu(NO_3)_2}=-302.9 kJ/mol

\Delta H_{f,CuO}=-157.3 kJ/mol

\Delta H_{f,NO_2}= 33.2 kJ/mol

\Delta H_{f,O_2}= 0 kJ/mol (standard state)

\Delta H_{rxn}=\sum [\Delta H_f(product)]-\sum [\Delta H_f(reactant)]

The equation for the enthalpy change of the given reaction is:

\Delta H_{rxn} =

=(2 mol\times \Delta H_{f,CuO}+4\times \Delta H_{f,NO_2}+1 mol\times \Delta H_{f,O_2})-(2mol\times \Delta H_{f,Cu(NO_3)_2})

\Delta H_{rxn}=

(2mol\times (-157.3 kJ/mol)+4\times 33.2 kJ/mol=1 mol\times 0 kJ/mol)-(2 mol\times (-302.9 kJ/mol)

\Delta H_{rxn}=424 kJ

The enthalpy change for the given reaction is 424 kJ.

6 0
4 years ago
Define saturated and unsaturated fats​
Sphinxa [80]

Answer:

<h3><u>Saturated and unsaturated</u>:-</h3>

Are a form of fat in which all or most of the fatty acid chains are single bonds. Glycerol and fatty acids are the two types of smaller molecules that make up fat.

<h3><u>Saturated fat is found in:</u></h3>
  • cakes
  • sausages
  • cheese
  • butter
<h3><u>Examples of unsaturated fats:- </u></h3>
  • Olive
  • Nuts(almonds, hazelnuts)
  • Seeds(pumpkin and sesame seeds)

hope it helps...

6 0
3 years ago
You are given a food containing 6 g protein per serving (30g), how much of the food you needto add to 100 ml solution to make a
Bas_tet [7]

Hey there!

500 mg of protein is present in 100 mL of solvent as per the concentration 0.5 mg/mL or 500 g/mL ,

So, 250 mg (0.25 g) of serving food need to be added to 100 mL solvent in order to prepare 50 mg of protein/100 mL solution.

Dilution factor = initial amount of protein / final amount of protein

= 6 g / 0.05 g = 120

Hope this helps!

4 0
4 years ago
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