I believe it means put the correct animal in the right category. Like for producer you would put the plant for herbivores you would put the type of insect that they are showing that eats the plant. I think that is what they are wanting you to do.
Answer:
Light is used by plants in a complex system that uses the light and several other resources to produce food. The more food= the more the plant grows, but too much food can be unhealthy for the plant. Some plants require more energy and others require less, this is because of the environment that they are in.
Explanation:
Answer:
D. <span>10 mol of solute/ 1L of solution
Explanation:
Molarity is used to express the concentration of the solution. It is expressed as the number of moles of solute per liter of solution
Molarity = moles of solute / liters of solution
This means that molarity has the units moles/liter
The only option satisfying this is the last one.
Hope this helps :)</span>
Answer:
40.68 % C
23.73 % N
8.47% H
27.12% O
Explanation:
The mass percent of an element X in a compound is calculated as the molar mass (MM) of X multiplied by the number of atoms of X in the compound, divided into the molecular weight (MW) of the compound, as follows:
mass percent of X = (MM(X) x number of atoms of X)/MW compound x 100
Thus, we first calculate the MW of acetamide (C₂H₅NO) by using the molar mass of the chemical elements C, H, N and O:
MW(C₂H₅NO) = (12 g/mol C x 2) + (1 g/mol H x 5) + 14 g/mol N + 16 g/mol O = 59 g/mol
Now, we can calculate the mass percent of each element (C, H, N, O) in C₂H₅NO:
- Mass percent of C (2 atoms of C in 1 molecule of C₂H₅NO):
% mass C = (12 g/mol x 2)/(59 g/mol) x 100 = 40.68 %
- Mass percent of N (1 atom of N in 1 molecule of C₂H₅NO):
% mass N = (14 g/mol x 1)/(59 g/mol) x 100 = 23.73 %
- Mass percent of H (5 atoms of H in 1 molecule of C₂H₅NO):
% mass H = (1 g/mol x 5)/(59 g/mol) x 100 = 8.47 %
- Mass percent of O (1 atom of O in 1 molecule of C₂H₅NO):
% mass O = (16 g/mol x 1)/(59 g/mol) x 100 = 27.12 %
The sum of the mass percents has to be equal to 100%:
40.68 % C + 23.73 % N + 8.47% H + 27.12% O = 100%