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svet-max [94.6K]
3 years ago
7

How many atoms are present in 65.39 g of zinc?

Chemistry
1 answer:
klio [65]3 years ago
3 0
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

 65.39 g Zn ( 1 mol / 65.38 g ) ( </span>6.022 x 10^23 atoms / 1 mol ) = 6.023x10^23 atoms Zn
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A chemist mixes 1.00 g CuCl2 with an excess of (NH4)2HPO4 in dilute aqueous solution . He measures the evolution of 670 J of hea
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Answer:

\Delta H will be 90054 J

Explanation:

Number of moles = (mass)/(molar mass)

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What is the molarity of solution that is 5.50 percentage by mass oxalic acid and has a density of 1.024 g/ml
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