Answer:
5.7 grams is the mass carbon dioxide gas inside a 3.0-L balloon.
Explanation:
Using ideal gas equation:
PV = nRT
where,
P = Pressure of carbon dioxide gas = 
V = Volume of carbon dioxide gas = 3.0 L
n = number of moles of carbon dioxide gas = ?
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of carbon dioxide gas =0°C = 0+273= 273 K
Putting values in above equation, we get:
Mass of 0.13 mole carbon dioxide gas :
= 0.13 mol × 44 g/mol = 5.7 g
5.7 grams is the mass carbon dioxide gas inside a 3.0-L balloon.
Answer:
The temperature will be 137 K for the gas pressure to remain constant
Explanation:
If the gas pressure keeps on constant, volume of the gas will be modified according to temperature.
V1 / T1 = V2 / T2
4L / 274K = 2L / T2
(4L / 274K) . T2 = 2L
T2 = 2L . (274K / 4L)
T2 = 137K
Answer:
Oxygen - Proportions increased as plants released this gas into the atmosphere.
Water Vapor - Proportions decreased as this lighter gas was blown away by solar winds.
Hydrogen - Proportions increased as this gas was released through volcanic eruptions.
Ammonia - Proportions decreased as it reacted with other elements to form nitrogen.
Carbon Dioxide - Proportions decreases as plants used this gas during photosynthesis.
Explanation:
HNO3(aq) is the compound produced by a neutralization
