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zvonat [6]
3 years ago
6

Which is the correct answer??

Chemistry
1 answer:
mestny [16]3 years ago
8 0

Answer:

1

Explanation:

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umka2103 [35]

Answer: In factories they burn coal under a giant container(a really big gumbo pot pretty much). when the fire is hot enough it starts to boil. When it boils it creates steam and the steam blows on a fan that makes electricity.

4 0
3 years ago
If i add water to 100 mL of a 0.15M NaOH solution until the final volume 150mL , what will the molarity of the diluted solution
labwork [276]
0,15 moles of NaOH-------in------------1000ml
x moles of NaOH------------in--------100ml
x = 0,015 moles of NaOH

final volume = 150ml

0,015 moles of NaOH---in-------150ml
x moles of NaOH--------------in-----1000ml
x = 0,1 moles of NaOH

answer:  0,1mol/dm³  (molarity)
3 0
3 years ago
How does fabric softener affect the flammability of different fabrics?
Karolina [17]
<span>Research shows that fabric softeners decrease flame resistance. The flame resistance of a fabric can be increased in a variety of ways. Most often, the fabric is treated with special flame resistant chemicals. Synthetic fabrics, such as polyester, are naturally flame resistant. These fabrics have a property called thermoplasticity, where the fabric naturally melts and shrinks when exposed to flame. This prevents these fabrics from igniting and burning as easily as other fabrics. Basic properties of a fabric, such as porosity, can also influence flame resistance. Larger pores allow for oxygen to be more present in the fabric, making it more flammable.</span>
5 0
3 years ago
The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c
netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is 4.58\times 10^{-3}M

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of oxygen gas

C_2\text{ and }p_2 are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used:  1 atm = 760 torr

C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm

Putting values in above equation, we get:

\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M

Hence, the solubility of oxygen gas at 628 torr is 4.58\times 10^{-3}M

4 0
2 years ago
Which sample has more atoms in it? 150.0 g of gold or 10.0 g of lithium.
Deffense [45]

Answer:150g of gold

Explanation: There is a lot more gold and gold is significantly significantly more dense than lithium

6 0
3 years ago
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