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Temka [501]
3 years ago
9

Which element is found in period 6 group 14​

Chemistry
1 answer:
kicyunya [14]3 years ago
7 0

Answer:

Lead

that can be found in the periodic table of elements

Explanation:

You might be interested in
What is one chemical reaction that begins with petroleum as a starting material
emmasim [6.3K]

Answer:

Thermal decomposition or cracking

Explanation:

Petroleum is a mixture of hydrocarbons which are usually formed naturally. Petroleum undergo a host of chemical reactions. One of such is thermal decomposition or cracking.

Cracking is used in the petroleum industry to covert heavy fractions to more useful lighter ones.

When petroleum is subjected to high temperature and pressure, and in the presence of catalyst, the long chain type of petroleum will decompose into more useful smaller and lighter molecules.

Example is given below:

                  C₁₅H₃₂ → C₈H₁₈ + C₃H₆ + 2C₂H₄

6 0
4 years ago
A dark brown binary compound contains oxygen and a metal. It is 13.38% oxygen by mass. Heating it moderately drives off some of
Leto [7]

Answer:

a) Mass of O in compound A = 32.72 g

Mass of O in compound B =  21.26 g

Mass of O in compound C = 15.94 g

b) Compound A = MO2

Compound B = M3O4

Compound C = MO

c) M = Pb

Explanation:

Step 1: Data given

A binairy compound contains oxygen (O) and metal (M)

⇒ 13.38 % O

⇒ 100 - 13.38 = 86.62 % M

After heating we get another binairy compound

⇒ 9.334 % O

⇒ 100 - 9.334 = 90.666 % M

After heating we get another binairy compound

⇒ 7.168 % O

⇒ 100 - 7.168 = 92.832 % M

The first compound has an empirical formula of MO2

⇒ 1 mol M for 2 moles O

Step 2: Calculate amount of metal and oxygen in each

compound A:   M  = m1 *0.8662    O = m1 *0.1338

compound B:   M  = m2 *0.90666    O = m2 *0.09334

compound C:   M  = m3 *0.92832    O = m3 *0.07168

Step 3: Calculate mass of oxygen with 1.000 grams of M

Compound A: 1.000g * 0.1338 m1gO  / 0.8662m1gMetal = 0.1545

Compound B: 1.000g * 0.09334 m2gO  / 0.90666m2gMetal = 0.1029

Compound C: 1.000g * 0.07168 m3gO  / 0.92832m3gMetal = 0.07721

Step 4:

1 mol MO2 has 1 mol M and 2 moles O

m1 = (mol O * 16)/0.1338   m1 = 239.2 grams

1 mol M = 0.8632*239.2 = 206.48

0.90666m2 = 206.48  ⇒ m2 = 227.74 g

0.92832m3 = 206.48  ⇒ m3 = 222.42 g

Step 5: Calculate mass of O

Mass of O in compound A = 239.2 - 206.48 = 32.72 g

Mass of O in compound B = 227.74 - 206.48 = 21.26 g

Mass of O in compound C = 222.42- 206.48 = 15.94 g

Step 6: Calculate moles

Moles of O in compound A ≈ 2

⇒ MO2

Moles of O in compound B = 21.26 / 16 ≈ 1.33

⇒ M3O4

Moles of O compound C = 15.94 /16 ≈ 1 moles

⇒ MO

Step 7: Calculate molar mass

The mass of 1 mol metal is 206.48 grams  ⇒ molar mass ≈ 206.48 g/mol

The closest metal to this molar mass is lead (Pb)

6 0
3 years ago
Which type of electromagnetic radiation has the longest wavelength?
Montano1993 [528]

Answer:

B. Infrared.

Explanation:

Referring to the electromagnetic spectrum, ultraviolet rays can be measured with a frequency of 10‐⁸, infrared has a frequency of 10‐⁵, visible radiation has a frequency of 0.5 x 10‐⁶ meanwhile X-rays show a frequency of 10‐¹⁰.

Hence, the largest magnitude among the rest goes to infrared rays, which makes B the correct answer.

8 0
4 years ago
Can someone please help me with this? This is due today, please please help me!
Elanso [62]
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2>

ATOMIC NUMBER: It is the number of protons present in the nucleus of every atom

MASS NUMBER: It is the number of nucleon. Nucleon are the number of proton and neutrons present in the nucleus.

PROTON NUMBER: Proton number equal to the atomic number.

ELECTRON NUMBER: Electron Number is equal to the atomic number.

NEUTRON NUMBER: It is Mass Number - Atomic Number.

CHARGE: It is due to the addition or removal of the electron. + charge when electron removed and - charge when electron is added.

SYMBOL: It is represented as,

                                                X^Z_A

Z is Mass Number

A is Atomic Number

<h2>_____________________________________</h2><h2>Worksheet:</h2>

(I) ATOMIC NUMBER: 17

    MASS NUMBER: 35.5

    PROTON NUMBER: 17

    ELECTRON NUMBER: 17

    NEUTRON NUMBER: 18.5

    CHARGE: 0

<h2>_____________________________________</h2>

(II) ATOMIC NUMBER: 71

    MASS NUMBER: 180

    PROTON NUMBER: 71

    ELECTRON NUMBER: 71

    NEUTRON NUMBER: 109

    CHARGE: 0

<h2>_____________________________________</h2>

(III)  ATOMIC NUMBER: 40

    MASS NUMBER: 86

    PROTON NUMBER: 40

    ELECTRON NUMBER: 38

    NEUTRON NUMBER: 46

    CHARGE: +2

<h2>_____________________________________</h2>

(IV)  ATOMIC NUMBER: 92

    MASS NUMBER: 238

    PROTON NUMBER: 92

    ELECTRON NUMBER: 86

    NEUTRON NUMBER: 146

    CHARGE: +6

<h2>_____________________________________</h2>

(V) ATOMIC NUMBER: 82

    MASS NUMBER: 206

    PROTON NUMBER: 82

    ELECTRON NUMBER: 78

    NEUTRON NUMBER: 124

    CHARGE: +4

<h2>_____________________________________</h2>

(VI) ATOMIC NUMBER: 34

    MASS NUMBER: 79

    PROTON NUMBER: 34

    ELECTRON NUMBER: 36

    NEUTRON NUMBER: 45

    CHARGE: -2

<h2>_____________________________________</h2>

(VII) ATOMIC NUMBER: 48

    MASS NUMBER: 113

    PROTON NUMBER: 48

    ELECTRON NUMBER: 49

    NEUTRON NUMBER: 65

    CHARGE: -1

<h2>_____________________________________</h2>

(VIII) ATOMIC NUMBER: 21

    MASS NUMBER: 42

    PROTON NUMBER: 21

    ELECTRON NUMBER: 21

    NEUTRON NUMBER: 21

    CHARGE: 0

<h2>_____________________________________</h2>

(IX) ATOMIC NUMBER:

    MASS NUMBER:

    PROTON NUMBER:

    ELECTRON NUMBER:

    NEUTRON NUMBER:

    CHARGE:

<h2>_____________________________________</h2>

(X) ATOMIC NUMBER: 83

    MASS NUMBER: 209

    PROTON NUMBER: 83

    ELECTRON NUMBER: 80

    NEUTRON NUMBER: 126

    CHARGE: +3

<h2>_____________________________________</h2>

(XI) ATOMIC NUMBER: 47

    MASS NUMBER: 108

    PROTON NUMBER: 47

    ELECTRON NUMBER: 47

    NEUTRON NUMBER: 61

    CHARGE: 0

<h2>_____________________________________</h2>

(XII) ATOMIC NUMBER: 49

    MASS NUMBER: 116

    PROTON NUMBER: 49

    ELECTRON NUMBER: 46

    NEUTRON NUMBER: 67

    CHARGE: +3

<h2>_____________________________________</h2>

(XIII) ATOMIC NUMBER: 53

    MASS NUMBER: 128

    PROTON NUMBER: 53

    ELECTRON NUMBER: 54

    NEUTRON NUMBER: 75

    CHARGE: -1

<h2>_____________________________________</h2>

(XIV) ATOMIC NUMBER: 76

    MASS NUMBER: 188

    PROTON NUMBER: 76

    ELECTRON NUMBER: 72

    NEUTRON NUMBER: 112

    CHARGE: +4

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h2 />
4 0
3 years ago
How are isotopes defined? forms of different elements that have the same number of neutrons in each atom forms of different elem
Gre4nikov [31]

Answer : The correct option is, forms of the same element that differ in the number of neutrons in each atom

Explanation :

Isotopes : It is defined as the forms of same element that have the same number of protons and electrons but differ in the number of neutrons.

For example : Carbon-12, carbon-13 and carbon-14 is an isotopes due to the same number of protons and electrons and different number of neutrons.

Carbon-12

Atomic number = 6

Atomic mass = 12

Atomic number = Number of protons = Number of electrons = 6

Number of neutrons = Atomic mass - Atomic number = 12 - 6 = 6

Carbon-13

Atomic number = 6

Atomic mass = 13

Atomic number = Number of protons = Number of electrons = 6

Number of neutrons = Atomic mass - Atomic number = 13 - 6 = 7

Carbon-14

Atomic number = 6

Atomic mass = 14

Atomic number = Number of protons = Number of electrons = 6

Number of neutrons = Atomic mass - Atomic number = 14 - 6 = 8

3 0
4 years ago
Read 2 more answers
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