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3 years ago

9

Which element is found in period 6 group 14

1 answer:

kicyunya [14]3 years ago

7 0

Answer:

Lead

that can be found in the periodic table of elements

Explanation:

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What was the action between the 2 atoms in an ionically bonded compound that caused that ionic bond to form in the first place?

Andreas93 [3]

Ionic bonds form between two elements that have a very large difference in electronegativity ie. a metal and a non-metal. The electronegative element will want an electron to make it stable whilst the less electronegative element wants to donate an electron to make it stable. Therefore the metallic element donates a electron to the non-metal and both become ions, which attract each other. Eg. Na becomes Na+ and Cl becomes Cl-, the opposite charges attract, forming the bond.

3 0

2 years ago

At constant pressure, density of gas is inversely proportional to its temperature. This is how hot air balloon is floating in ai

Arturiano [62]

Answer:

1.08 g/L is the density of air.

Explanation:

Pressure of the gas = P (atm)

Volume of the gas = V (L)

Moles of gas = n = $\frac{w(g)}{M(g/mol)}$

Temperature of the gas = T (K)

$PV=nRt$

$PV=\frac{w}{M}\times RT$

$PM=\frac{w}{V}RT=DRT$

where:

D = density of the gas = $\frac{Mass}{Volume}$

R = universal gas constant

w = Mass of the gas

M =Molar mass of the gas

Given = P = 1.0 atm , T = 54°C = 327.15 K

Average molar mass of the gas = 29 g/mol

Putting all the given values in above equation.

$1 atm\times 29 g/mol=D\times 0.0821 atm L/mol K\times 327.15 K$

$D=\frac{1 atm\times 29 g/mol}{0.0821 atm L/mol K\times 327.15 K}$

D = 1.08 g/L

1.08 g/L is the density of air.

3 0

2 years ago

A chemist must prepare 575.mL of 1.00M aqueous sodium carbonate Na2CO3 working solution. He'll do this by pouring out some 1.58M

igor_vitrenko [27]

Answer : The volume in mL of the sodium carbonate stock solution is 364 mL.

Explanation :

According to dilution law:

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of aqueous sodium carbonate

$M_2$ = molarity of aqueous sodium carbonate stock solution

$V_1$ = volume of aqueous sodium carbonate

$V_2$ = volume of aqueous sodium carbonate stock solution

Given:

$M_1$ = 1.00 M

$M_2$ = 1.58 M

$V_1$ = 575 mL

$V_2$ = ?

Now put all the given values in the above formula, we get:

$1.00M\times 575mL=1.58M\times V_2$

$V_2=363.92mL\approx 364mL$

Therefore, the volume in mL of the sodium carbonate stock solution is 364 mL.

8 0

2 years ago

Between which two stages does cell division (cells divide or multiple) first occur?

anygoal [31]

I think the answer is C. C and D

8 0

2 years ago

The total mass of the reactants is equal to the total mass of products. this is known as the conservation of what?

rodikova [14]

Explanation:

the law of conservation of mass

6 0

1 year ago