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3 years ago

The formula for density is ____ divided by volume. mass ounces weight

Chemistry

2 answers:

neonofarm [45]3 years ago

8 0

The answer is mass which is also m/v=d

ra1l [238]3 years ago

6 0

Answer:

a) mass

Explanation:

density = mass/volume

Ounces are units of volume. Weight is not the same thing as mass. Weight has to do with gravity. Mass remains constant as a scalar quantity whereas weight is a vector quanitiy. For instance, although you'd have mass in outer space, you would have no weight. The simple answer is because there is no gravity in outer space. Thus, the formula for density is d = m/V.

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Issue like gay marriage, abortion, and education have caused debate over the constitution because of the issue of what? (Hint: f

Korolek [52]

Yes 81671 cupcake ham shops

3 0

2 years ago

Consider this initial-rate data at a certain temperature for the reaction described by N2O3(

Yuliya22 [10]

N2O3(g)→NO(g)+NO2(g)

[N2O3] Initial Rate
0.1 M r(t)=0.66 M/s
0.2 M r(t)=1.32 M/s
0.3 M r(t)=1.98 M/s

We can have the relationship:

([N2O3]/[N2O3]0)^m=r(t)/r0(t)
However,
([N2O3]/[N2O3]0) = 2

Also, we assume m=1 which is the order of the reaction.

Thus, the relationship is simplified to,

r(t)/r0(t) = 2

r(t)=k[N2O3]

0.66 M/s=k×0.1 M

k=6.6 s−1

6 0

3 years ago

Read 2 more answers

Which of the followings is true about G0'? A. G0' can be determined using Keq' B. G0' indicates if a reaction can occur under no

nekit [7.7K]

Answer:

A and D are true , while B and F statements are false.

Explanation:

A) True. Since the standard gibbs free energy is

ΔG = ΔG⁰ + RT*ln Q

where Q= [P1]ᵃ.../([R1]ᵇ...) , representing the ratio of the product of concentration of chemical reaction products P and the product of concentration of chemical reaction reactants R

when the system reaches equilibrium ΔG=0 and Q=Keq

0 = ΔG⁰ + RT*ln Q → ΔG⁰ = (-RT*ln Keq)

therefore the first equation also can be expressed as

ΔG = RT*ln (Q/Keq)

thus the standard gibbs free energy can be determined using Keq

B) False. ΔG⁰ represents the change of free energy under standard conditions . Nevertheless , it will give us a clue about the ΔG around the standard conditions .For example if ΔG⁰>>0 then is likely that ΔG>0 ( from the first equation) if the temperature or concentration changes are not very distant from the standard conditions

C) False. From the equation presented

ΔG⁰ = (-RT*ln Keq)

ΔG⁰>0 if Keq<1 and ΔG⁰<0 if Keq>1

for example, for a reversible reaction ΔG⁰ will be <0 for forward or reverse reaction and the ΔG⁰ will be >0 for the other one ( reverse or forward reaction)

D) True. Standard conditions refer to

T= 298 K

pH= 7

P= 1 atm

C= 1 M for all reactants

Water = 55.6 M

5 0

3 years ago

When butane burns completely, only water and carbon dioxide gas are produced. If 11.6 g of butane and 40.0 L of oxygen at 22.0o

Angelina_Jolie [31]

19.7 litre volume of carbon dioxide gas at 22.0o C and 102 kPa can be collected over water.

<h3>What is vapour pressure?</h3>

Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature.

Moles of Butane = mass in grams / molar mass = 11.6 / 58.12 = 0.2

Volume of $O_2$ (V) = 40 liter

Temperature (T) = 22°C = 22 + 273 = 295 K

Pressure (P) = 102 kPa = 102 / 101.325 = 1.007 atm

Moles of $O_2$ (n) can be calculated by ideal gas equation.

PV = nRT

n = 1.007 40 ÷ 0.0821 295 = 1.663

Balanced chemical reaction;

2 $C_4H_10$ + 13 $O_2$ ---> 8 $CO_2$ + 10 $H_2O$

From reaction;

13 moles $O_2$ require 2 moles $C_4H_10$

So, 1.663 moles $O_2$ will require = 2 x 1.663 ÷13 = 0.256 moles of $C_4H_10$

Thus $C_4H_10$ is a limiting reagent. So it will drive the yield of $CO_2$ .

Moles of $CO_2$ produced = (8/2) 0.2 = 0.8 moles

Pressure of $CO_2$ (P) = 102 - 2.24 = 99.76 kPa = 99.76 ÷ 101.325 = 0.985 atm

Applying the ideal gas equation for $CO_2$ ,

PV = nRT

0.985 V = 0.8 0.0821 x 295

V = 19.7 liter

The volume of $CO_2$ produced = 19.7 liter.

Learn more about the vapour pressure here:

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5 0

2 years ago

Draw the Lewis structure for the compound with the formula COCl2COCl2. Use lines to show bonding electrons.

stira [4]

Answer : The Lewis-dot structure of $COCl_2$ is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, $COCl_2$

As we know that carbon has '4' valence electrons, chlorine has '7' valence electron and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in $COCl_2$ = 1(4) + 2(7) + 1(6) = 24

According to Lewis-dot structure, there are 8 number of bonding electrons and 16 number of non-bonding electrons.

6 0

3 years ago