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zepelin [54]
2 years ago
8

What do we beileve is at the center of the milky way

Chemistry
1 answer:
BaLLatris [955]2 years ago
5 0

Answer:

I think the answer is C because I know

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Using VSEPR theory which of the following would be the correct shape for nitrogen trifluoride?
RUDIKE [14]

Answer:

trigonal pyramidal

Explanation:

In NF3, the nitrogen atom is sp3 hybridized. Now we must remember that according to the VSEPR theory, the number of electron pairs in the valence shell of the central atom in a molecule determines its shape.

Here, the nitrogen atom is the central atom and its outermost shell is surrounded by four electron pairs - one lone pair and three bond pairs. This means that it has a tetrahedral electron pair geometry.

However, due to the lone pair, the three fluorine atoms are arranged in a  trigonal pyramidal geometry. Hence the correct shape of the molecule is trigonal pyramidal.

6 0
2 years ago
Differentiate between elements and mixtures
Ksenya-84 [330]

Answer:

ELEMENTS MIXTURE

Elements are made up of one kind of atoms. Mixtures are made up of two or more kinds of Compounds .

Elements cannot be broken down into simpler substances by any physical or chemical method. The various constituents are seperated by simple physical means

3 0
2 years ago
Read 2 more answers
If you were givin 2.50 moles of.sodium bromide, how many grams of salt do you have
mihalych1998 [28]

Answer: 257.23

Explanation:

7 0
3 years ago
If you start with 30 moles of O2, how many moles of SiO2 can you make?
Ivanshal [37]

Answer:

30moles of SiO₂

Explanation:

Given parameters:

Number of moles of O₂  = 30moles

Unknown:

Number of moles of SiO₂  = ?

Solution:

To solve this problem, we need to write the reaction expression:

       Si +  O₂  →  SiO₂  

The reaction is balanced;

      1 mole of O₂ will produce 1 mole of SiO₂

     30mole of O₂ will produce 30moles of SiO₂

7 0
3 years ago
A mixture contains NaHCO3 together with unreactive components. A 1.75 g sample of the mixture reacts with HA to produce 0.561 g
Lynna [10]

Answer:

\%NaHCO_3=61.2\%

Explanation:

Hello.

In this case, since the undergoing chemical reaction is only between the sodium bicarbonate and the acid HA:

NaHCO_3+HA\rightarrow NaA+H_2O+CO_2

For 0.561 g of yielded carbon dioxide (molar mass 44 g/mol), the following mass of sodium bicarbonate (molar mass 84 g/mol) that reacted was:

m_{NaHCO_3}=0.561gCO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molNaHCO_3}{1molCO_2} *\frac{84gNaHCO_3}{1molNaHCO_3} \\\\m_{NaHCO_3}=1.071g

Considering the 1:1 mole ratio between CO2 and NaHCO3. Finally, the percent by mass of NaHCO3 is computed by dividing the mass of reacted NaHCO3 and t the mixture:

\%NaHCO_3=\frac{1.071g}{1.75g}*100\%\\ \\\%NaHCO_3=61.2\%

Best regards.

5 0
3 years ago
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