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satela [25.4K]
3 years ago
6

What is the net ionic equation of the reaction of mgcl2 with naoh?

Chemistry
1 answer:
AveGali [126]3 years ago
7 0

Answer:

The net ionic equation will be MgCl₂ + 2  NaOH → Mg(OH)₂ + 2 NaCl

Explanation:

Ionization of MgCl₂ is as follows

MgCl₂  → Mg²⁺ + 2 Cl⁻

Ionization of NaOH is as follows

NaOH → Na⁺ + OH⁻

It  is a one type of substitution reaction where OH⁻ combined with  Mg²⁺ to give magnesium hydroxide .

 On the other hand Cl⁻ combined with Na⁺ to give sodium chloride as product.

Using proper stoichiometry to balanced the number of atoms in both side .

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Sodium chloride is the chemical name for salt and is composed of sodium and chlorine, so it is a compound.

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Explanation:

Follow PEMDAS. 7x12 = 84

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The volume of the ideal gas in the container is 9 m3. What would the volume be if four more blocks were placed on top of the lid
7nadin3 [17]
Answer;
             4.5 m³

Solution:
              The statement says that two blocks are present on a lid of a container with volume of 9 m³. The mass of lid is equal to the mass of two blocks. It means that initially there are four blocks (or four atm pressure) upon 9 m³ volume. 

After that four more blocks are placed on the lid. Means the pressure is increased from 4 atm to 8 atm (2 atm of lid, 2 atm of old blocks, 4 atm of new four blocks).

So, Data generated is,

                  P₁  =  4 atm

                  V₁  =  9 m³

                  P₂  =  8 atm

                  V₂  =  ?

According to Boyle's Law,

                               P₁ V₁  =  P₂ V₂

Solving for V₂,
                               V₂  =  P₁ V₁ / P₂

Putting values,
                               V₂  =  (4 atm × 9 m³) ÷ 8 atm

                               V₂  =  4.5 m³
0 0
4 years ago
Calculate your % yield of co2 in the reaction based on the grams of nahco3 being the limiting reagent in the reaction.
Lynna [10]

The percent yield of CO₂ is 93.3%.

<h3>What is the percent yield of CO₂?</h3>

The percent yield of a substance is given as follows:

  • Percent yield = actual yield/theoretical yield * 100 %

The equation of the reaction is used to determine the theoretical yield.

  • NaHCO₃ + CH₃COOH → CH₃COONa + H₂O + CO₂

Moe ratio of sodium bicarbonate and CO₂ is 1 : 1.

Given that sodium bicarbonate is the limiting reactant, the theoretical yield of CO₂ will be:

Moles of NaHCO₃ reacting = 2.01/84 = 0.0239 moles

Theoretical yield of CO₂ = 0.0239 moles * 22.4L/mol = 0.536 L

Actual yield = 0.50 L

Percent yield = 0.50/0.536 * 100%

Percent yield = 93.3%

In conclusion, the percent yield is the ratio of the actual yield and theoretical yield.

<em>Note that the complete question is given below:</em>

<em>Calculate your % yield of co2 in the reaction based on the grams of nahco3 being the limiting reagent in the reaction between 2.01 g of sodium bicarbonate and 24.6 mL of 1.5 M acetic acid? They produce 0.50 L of at s.t.p.</em>

<em />

Learn mores about percent yield at: brainly.com/question/8638404

#SPJ1

3 0
2 years ago
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